2 years ago

Solve for x: (x2−2x)2−8 = 7(x2−2x)

Mathematics

2 answers:

Marrrta [24]2 years ago

8 0

Answer:

x1= -2

x2= 1

x3= 4

Step-by-step explanation:

gregori [183]2 years ago

6 0

$\\ \sf\longmapsto (x^2-2x)^2-8=7(x^2-2x)$

$\\ \sf\longmapsto x^4-4x^3+2x^2-8=7x^2-14x$

$\\ \sf\longmapsto x^4-4x^3-5x^2+14x-8=0$

No real roots (pic attached)

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