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Mrac [35]
3 years ago
13

Solve for x: (x2−2x)2−8 = 7(x2−2x)

Mathematics
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

x1= -2

x2= 1

x3= 4

Step-by-step explanation:

gregori [183]3 years ago
6 0

\\ \sf\longmapsto (x^2-2x)^2-8=7(x^2-2x)

\\ \sf\longmapsto x^4-4x^3+2x^2-8=7x^2-14x

\\ \sf\longmapsto x^4-4x^3-5x^2+14x-8=0

No real roots (pic attached)

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