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Genrish500 [490]
2 years ago
12

Ey pls help me anyone pls

Mathematics
2 answers:
polet [3.4K]2 years ago
7 0

Answer:

I will do 1-4 and explain because I dont have the time to do all of this.

1=130 2=130 3=134? 4=63 Just add up the numbers and subtract them from either 90 180 or 360, how to know which number to add up to is easy, just see if the sum of the numbers added makes a number above one of those numbers, for example if you find one that the sum is larger then 90 but smaller then 180 then subtract the sum from 180.

Step-by-step explanation:

Sidana [21]2 years ago
3 0

Answer:

we cant read the whole question so I cant help you.

Step-by-step explanation:

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When 31 times a number is increased by 40, the answer is the same as when 200 is decreased by the number
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3 years ago
A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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4 years ago
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Explain

That’s hard
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Step by step solutions
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3 years ago
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