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Oksi-84 [34.3K]
3 years ago
7

The area of a trapezium shaped field is 480m the distance between two parlel sides is 15m and one of the parrellel side is 20m f

ind the other parralel side
Mathematics
1 answer:
Annette [7]3 years ago
7 0

The other parallel side is 44 m

Step-by-step explanation:

Let us revise the formula of the area of a trapezium

A=\frac{1}{2}(b_{1}+b_{2})h , where

  • b_{1} and b_{2} are its parallel bases
  • h is its height (The distance between the two parallel bases)

∵ The area of a trapezium is shaped field is 480 m²

∴ A = 480 m²

∵ The distance between two parallel sides is 15 m

∴ h = 15 m

∵ One of the parallel side is 20 m

∴ b_{1} = 20 m

We need to find b_{2}

Substitute all these value in the rule of the area below

∵ A=\frac{1}{2}(b_{1}+b_{2})h

∴ 480=\frac{1}{2}(20+b_{2})(15)

- Multiply the two sides by 2

∴ 960=(20+b_{2})(15)

- Divide both sides by 15

∴ 64=20+b_{2}

- Subtract 20 from both sides

∴ 44=b_{2}

The other parallel side is 44 m

Learn more:

You can learn more about trapezium in brainly.com/question/7287774

#LearnwithBrainly

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I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

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