Answer:
Step-by-step explanation:
For the null hypothesis,
µ = 60
For the alternative hypothesis,
h1: µ < 60
This is a left tailed test
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 52
µ = population mean = 60
s = samples standard deviation = 22
t = (52 - 60)/(22/√100) = - 3.64
We would determine the p value using the t test calculator. It becomes
p = 0.00023
We would reject the null hypothesis if α = 0.05 > 0.00023
16.22 divided by 2 = your answer. (8.11)
Since 25% is 1/4 divide 28 by 4 to get your answer of 9.5
31252130405 is the answer :)
Ah, thank you. your question truly made the most of sense.
