Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)
Answer:
there was alot of math here but i got 10
Step-by-step explanation:
so first u add 10 and 2 u get 12 then u multiply 4 then u get 48 and divide that by 4 and then subtract 2 and get 10. hope this helped
Answer:
Adjacent leg (In relation to the angle that is measure 22 degrees)= 70*Cosine 22 or 64.9; Opposite leg (In relation to the angle that is measure 22 degrees)=70* Sin 22 or 26.22
Step-by-step explanation:
The other angle measure is 90-22 or 68.
To find the length of the adjacent leg (a) use cosine. Remember cosine is Adjacent leg over hypotenuse.
Cosine 22= a/70- Multiply by 70
70* Cosine 22=a or about 64.9
To find the length of the opposite leg (o) use sine. Remember sine is Opposite leg over hypotenuse
Sine 22= o/70
70*Sine 22=o
o= about 26.22
Change the mixed fractions to improper fractions.
To do this, multiply the whole number part by the denominator. Add that to the numerator. Then write the result on top of the denominator.
You would now have:
Change the division sign to a multiplication sign by turning the second fraction upside down.
That is,
The answer is:
This can be simplified to:
Answer:
f(x) = 8x⁴-8x²+1
Step-by-step explanation:
I will assume that f(cos θ) = cos(4θ). Otherwise, f would not be a polynomial. lets divide cos(4θ) in an expression depending on cos(θ). We use this properties
- cos(2a) = cos²(a) - sin²(b)
- sin(2a) = 2sin(a)cos(a)
- sin²(a) = 1-cos²(a)
cos(4θ) = cos(2 * (2θ) ) = cos²(2θ) - sin²(2θ) = [ cos²(θ)-sin²(θ) ]² - [2cos(θ)sin(θ)]² = [cos²(θ) - ( 1 - cos²(θ) ) ]² - 4cos²(θ)sin²(θ) = [2cos²(θ)-1]² - 4cos²(θ) (1 - cos²(θ) ) = 4 cos⁴(θ) - 4 cos²(θ) + 1 - 4 cos²(θ) + 4 cos⁴(θ) = 8cos⁴(θ) - 8 cos²(θ) + 1
Thus f(cos(θ)) = 8 cos⁴(θ) - 8 cos²(θ) + 1, and, as a result
f(x) = 8x⁴-8x²+1.
