Ask question

Ask question

All categories

2 years ago

8

Can someone answer this please

1 answer:

Ulleksa [173]2 years ago

7 0

The scale used to make the model was 125 meters = 1 foot. 525 divided by 4.2 equals 125 meters.
The mode is 84 sheets of plywood tall.
4.2 feet = 50.4 meters
50.4 meters divided by 0.6 equals 84 sheets.

You might be interested in

Tonya has 39 packages.Each package weighs 6 pounds.<br> a.2,400lb<br> b.240lb<br> c.200lb<br> d20lb

Umnica [9.8K]

Each package weighs 6 pounds. Choose the best estimate of the total weight of the packages.2,400 pounds 240 pounds 200 pounds 20 pounds.

3 0

2 years ago

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Determine whether each equation is a linear equation. Write yes or no. If yes, write the equation in standard form.

Svetllana [295]

This is indeed a linear equation. y-4x=9 in standard form is y=4x+9.

8 0

3 years ago

Read 2 more answers

Which operation should be performed first according to the order of operations?

Hunter-Best [27]

Answer:

your answer is c 24 divided by 3

Step-by-step explanation:

PEMDAS

Parenthesis/exponents/multiplication and division from left to right/addition and subtraction from left to right

5 0

2 years ago

Black_prince [1.1K]

C:x, in the bottom equation

4 0

2 years ago