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azamat
3 years ago
7

Find the equation for the horizontal line that goes through the point V(-5,17)

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:

x = -5

Step-by-step explanation:

x = -5 because a horizontal line does not change in y value

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McKenzie bought 4 blow pops for $2.00 from the concession stand. How much would she have to pay for 13 blow pops at this rate?
Verdich [7]

Answer:

$6.50

Step-by-step explanation:

If she bought 4 blow pops for $2.00, each blow pop is $0.50.

You then multiply the cost for each blow pop ($0.50) by the number of blow pops she will buy (13).

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3 years ago
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1/4 of a carton of 12 eggs to make an omelet how many did she use ?
Svetach [21]
3 eggs is 1/4 of 12 hope this helps :)
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In a 3-digit number, the middle digit is 3 times the last digit and 4 more than the first digit. All the digits are odd and can
Alexeev081 [22]

Answer:

5

Step-by-step explanation:

This is quite some trial and error question.

Based on the question, the numbers we can use are 1,3,5,7 and 9.

We will start with the middle digit first.

Since the question has stated it is 3 times the last digit, the number has to be in multiples of 3.

So we are left with: 3 and 9.

Then, the question also states the middle digit is 4 more than the first digit. See, its a digit, so the value cannot be less than 1 (odd numbers only and no negative values), so if we subtract 4 to the middle digit to find the first, it should still be a Positive Single numerical value.

3 - 4 = -1

9 - 4 = 5

Therefore, this middle digit is = 9.

Since we know the middle digit = 9

The first digit will be 9 - 4 = 5

The whole value is now 593.

4 0
3 years ago
Highest common factor of 15 and 20
Vikki [24]

Answer:

The highest common factor is 5

Step-by-step explanation:

3x5=15  4x5=20

7 0
3 years ago
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The closed form sum of
zalisa [80]

Perhaps you know that

S_2 = \displaystyle\sum_{k=1}^n k^2 = \frac{n(n+1)(2n+1)}6

and

S_3 = \displaystyle\sum_{k=1}^n k^3 = \frac{n^2(n+1)^2}4

Then the problem is trivial, since

\displaystyle\sum_{k=1}^n k^2(k+1) = S_2 + S_3 \\\\ = \frac{2n(n+1)(2n+1)+3n^2(n+1)^2}{12} \\\\ = \frac{n(n+1)\big((2(2n+1)+3n(n+1)\big)}{12} \\\\ = \frac{n(n+1)\big(4n+2+3n^2+3n\big)}{12} \\\\ = \frac{n(n+1)(3n^2+7n+2)}{12} \\\\ = \frac{n(n+1)(3n+1)(n+2)}{12}

Then

12\bigg(1^2\cdot2+2^2\cdot3+3^2\cdot4+\cdots+n^2(n+1)\bigg) = n(n+1)(n+2)(3n+1)

so that <em>a</em> = 3 and <em>b</em> = 1.

4 0
3 years ago
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