Given:
The given sets are:
To find
The set .
Solution:
We have,
Now, is the set that contains all the common elements of both sets B and U.
Therefore, the correct option is A.
Ms. Cobb divided a bag of 24 chocolate candies between Bob and Patrick. Bob received 4s of candy for every 2
1 answer:
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Answer:
4z + 6z²
Step-by-step explanation:
(12z + 18z² ) ← multiply each term in the parenthesis by
= 4z + 6z²
1. 1, 2, 3 has 3! = 6 possible permutations:
1 2 3 // 1 3 2 // 2 1 3 // 2 3 1 // 3 1 2 // 3 2 1
2. T, V, W taken 2 at a time has possible permutations:
T V // T W // V T // V W // W T // W V
3. I'll replace these symbols with f, s, h, and t (face, sun, heart, triangle). This sequence has possible permutations:
f s // f h // f t // s f // s h // s t // h f // h s // h t // t f // t s // t h
4. This has 4! = 24 possible permutations.
A B C D // A B D C // A C B D // A C D B // A D B C // A D C B //
B A C D // B A D C // B C A D // B C D A // B D A C // B D C A //
C A B D // C A D B // C B A D // C B D A // C D A B // C D B A //
D A B C // D A C B // D B A C // D B C A // D C A B // D C B A
Answer:
See solution below.
Step-by-step explanation:
