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2 years ago

9

I need help with this maths homework please

1 answer:

valentinak56 [21]2 years ago

4 0

I found this on another question made before

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WILL GIVE BRAIINLIEST ANSWER Tomas is at least 7 years older than Larry. If Tomas is 16 years old, how old is Larry?

ra1l [238]

Larry - ( 9 years old )

8 0

3 years ago

Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer

Andrews [41]

Answer:

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

Step-by-step explanation:

Given

$(x_1,y_1) = (2,\frac{2}{3})$

$(x_2,y_2) = (3,\frac{5}{9})$

Required

Write the equation of the function $f(x) = ab^x$

Express the function as:

$y = ab^x$

In: $(x_1,y_1) = (2,\frac{2}{3})$

$y = ab^x$

$\frac{2}{3} = a * b^2$ --- (1)

In $(x_2,y_2) = (3,\frac{5}{9})$

$y = ab^x$

$\frac{5}{9} = a * b^3$ --- (2)

Divide (2) by (1)

$\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}$

$\frac{5}{9}/\frac{2}{3} = b$

$\frac{5}{9}*\frac{3}{2} = b$

$\frac{5}{3}*\frac{1}{2} = b$

$\frac{5}{6} = b$

$b = \frac{5}{6}$

Substitute 5/6 for b in (1)

$\frac{2}{3} = a * b^2$

$\frac{2}{3} = a * \frac{5}{6}^2$

$\frac{2}{3} = a * \frac{25}{36}$

$a = \frac{2}{3} * \frac{36}{25}$

$a = \frac{2}{1} * \frac{12}{25}$

$a = \frac{24}{25}$

The function: $f(x) = ab^x$

$f(x) = \frac{24}{25} * \frac{5}{6}^x$

7 0

2 years ago

A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol

iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let $x_1$ be the number of widgets sold and $x_2$ be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

$x_1+x_2=350...(1)$

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

$35x_1+22x_2=9,000...(2)$

From equation (1), we will get:

$x_2=350-x_1$

Substitute this value in equation (2):

$35x_1+22(350-x_1)=9,000$

$35x_1+7,700-22x_1=9,000$

$13x_1+7,700=9,000$

$13x_1+7,700-7,700=9,000-7,700$

$13x_1=1,300$

$\frac{13x_1}{13}=\frac{1,300}{13}$

$x_1=100$

Therefore, the company sold 100 widgets.

Substitute $x_1=100$ in equation (1):

$100+x_2=350$

$100-100+x_2=350-100$

$x_2=250$

Therefore, the company sold 250 gizmos.

3 0

2 years ago

Read 2 more answers

Mark this question "True" if the argument is VALID, and "False" if the argument is INVALID: If this number is larger than 6, the

sleet_krkn [62]

This argument is no valid although the first part of the statement is valid. If a number is larger than 6 than its square must be larger than 36. But if the number is smaller than 6, its square does not need to be smaller than 36. For example...

(-100)²=10000

-100 is smaller than 6 but its square is bigger.

answer: False

7 0

3 years ago

Help please ..........

Pie

Answer:

#2 is the closest to the actual roots.

Step-by-step explanation:

$12x^{3} -65x^{2} +24x+10=0$

$\frac{2}{3}$ is not a root, but 0.68078 is.

The other roots are -0.24572 and 4.9816. The closest option is #2.

5 0

2 years ago