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creativ13 [48]
2 years ago
9

I need help with this maths homework please

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0
I found this on another question made before

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WILL GIVE BRAIINLIEST ANSWER Tomas is at least 7 years older than Larry. If Tomas is 16 years old, how old is Larry?
ra1l [238]
Larry - ( 9 years old )
8 0
3 years ago
Enter an equation for the function that includes the points.Give your answer in a(b)x. In the event that a=1 , give your answer
Andrews [41]

Answer:

f(x) = \frac{24}{25} * \frac{5}{6}^x

Step-by-step explanation:

Given

(x_1,y_1) = (2,\frac{2}{3})

(x_2,y_2) = (3,\frac{5}{9})

Required

Write the equation of the function f(x) = ab^x

Express the function as:

y = ab^x

In: (x_1,y_1) = (2,\frac{2}{3})

y = ab^x

\frac{2}{3} = a * b^2 --- (1)

In (x_2,y_2) = (3,\frac{5}{9})

y = ab^x

\frac{5}{9} = a * b^3 --- (2)

Divide (2) by (1)

\frac{5}{9}/\frac{2}{3} = \frac{a*b^3}{a*b^2}

\frac{5}{9}/\frac{2}{3} = b

\frac{5}{9}*\frac{3}{2} = b

\frac{5}{3}*\frac{1}{2} = b

\frac{5}{6} = b

b = \frac{5}{6}

Substitute 5/6 for b in (1)

\frac{2}{3} = a * b^2

\frac{2}{3} = a * \frac{5}{6}^2

\frac{2}{3} = a * \frac{25}{36}

a = \frac{2}{3} * \frac{36}{25}

a = \frac{2}{1} * \frac{12}{25}

a = \frac{24}{25}

The function: f(x) = ab^x

f(x) = \frac{24}{25} * \frac{5}{6}^x

7 0
2 years ago
A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol
iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let x_1 be the number of widgets sold and x_2 be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

x_1+x_2=350...(1)

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

35x_1+22x_2=9,000...(2)

From equation (1), we will get:

x_2=350-x_1

Substitute this value in equation (2):

35x_1+22(350-x_1)=9,000

35x_1+7,700-22x_1=9,000

13x_1+7,700=9,000

13x_1+7,700-7,700=9,000-7,700

13x_1=1,300

\frac{13x_1}{13}=\frac{1,300}{13}

x_1=100

Therefore, the company sold 100 widgets.

Substitute x_1=100 in equation (1):

100+x_2=350

100-100+x_2=350-100

x_2=250

Therefore, the company sold 250 gizmos.

3 0
2 years ago
Read 2 more answers
Mark this question "True" if the argument is VALID, and "False" if the argument is INVALID: If this number is larger than 6, the
sleet_krkn [62]

This argument is no valid although the first part of the statement is valid. If a number is larger than 6 than its square must be larger than 36. But if the number is smaller than 6, its square does not need to be smaller than 36. For example...

(-100)²=10000

-100 is smaller than 6 but its square is bigger.

answer: False

7 0
3 years ago
Help please ..........
Pie

Answer:

#2 is the closest to the actual roots.

Step-by-step explanation:

12x^{3} -65x^{2} +24x+10=0

\frac{2}{3} is not a root, but 0.68078 is.

The other roots are -0.24572 and 4.9816.  The closest option is #2.

5 0
2 years ago
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