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creativ13 [48]
3 years ago
9

I need help with this maths homework please

Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0
I found this on another question made before

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Using the following diagram below, please answer the following:
Colt1911 [192]
The radius of the circle is 15 cm,
The diameter of the circle is 30 cm,
The circumference of the circle is 94.248 cm,
The area of the circle is 706.86 cm^2

The radius is given in the diagram as half the circle, which is 15 cm.

The diameter is double the radius because the diameter measures the circle from edge to edge, so 15•2=30 cm.

The circumference of the circle is 2•3.14•r=C,
2•3.14=6.28, 6.28•15= 94.248 cm.

The area of the circle is 3.14•r^2, so the radius squared is 225 (15•15) and 225•3.14=706.86 cm squared :)
7 0
3 years ago
If 120% is £48, what is 100%
azamat

Answer:

40

Step-by-step explanation:

If we go by 20's (20% of 100) 100% is 5. Since were dealing with 120% in our case we'll be dividing by 6 <u>to figure out what every 20% is</u>. All we need to do it's divide 48 by 6 and we get the answer 8. So in our case every 20% is equal to 8. now to solve for 100% all we need to do is subtract 8 (20%) from 120% (48) and we find 100% is 40. We could also do 8 x 5. (<em>remember every 1 is 20% in our case</em>) which is also 40. Therefore, your answer is 40.

If you don't quite understand what I'm talking about please let me know and I'll elaborate.. thanks! have a nice day and good luck with your quiz!

6 0
4 years ago
(x+6) + (x+8) + 14 / 2
wlad13 [49]
Answer=2x+21 do you want the whole solution?
3 0
3 years ago
Read 2 more answers
156 rounded to the nearest hundred is?
aliina [53]
200 because 156 is closer to 200 than 100
6 0
3 years ago
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2 : S
ziro4ka [17]

Answer:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Sample of 421 new car buyers, 75 preferred foreign cars. So n = 421, \pi = \frac{75}{421} = 0.178

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

8 0
3 years ago
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