The amount of money he lose on the last tool set is: $30.60.
<h3>Amount lose</h3>
Using this formula
Amount lose=Original amount paid -Selling price
Where:
Original amount paid=$54.60
Selling price=$24.00
Let plug in the formula
Amount lose=$54.60-$24.00
Amount lose=$30.60
Therefore the amount of money he lose on the last tool set is: $30.60.
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The answer would be 620000
What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
The events of rolling the dice are independent (i.e. they don't affect one another) so:
E.g.
P(6∩1) = P(6) * P(1)
P(2∩5) = P(2) * P(5)
The probability of getting a given number on a roll is 1/6 for both dice.
So:
P(6∩1) = 1/6 * 1/6 = 1/36
This is the same for any arrangement of numbers you could get from rolling two dice.
So, we can see that there are 6 arrangements of numbers that will give a sum of 7 and so that is 6 * 1/36 = 6/36 = 1/6
They are different the fraction 3/5 is 0.6 in decimal,and the fraction 6/15 is 0.4 in decimal.
Wish that helped.
Answer:
So, the required width of rectangular piece of aluminium is 8 inches
Step-by-step explanation:
We are given:
Perimeter of rectangular piece of aluminium = 62 inches
Let width of rectangular piece of aluminium = w
and length of rectangular piece of aluminium = w+15
We need to find width i.e value of x
The formula for finding perimeter of rectangle is: 
Now, Putting values in formula for finding Width w:
After solving we get the width of rectangular piece :w = 8
So, the required width of rectangular piece of aluminium is 8 inches
