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WINSTONCH [101]
3 years ago
13

Simplify 3a^2b^3c^5 __________________ 8x^4y^3z

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).
\frac{3a ^{2} b ^{3}c ^{5}  }{8 x^{4}y ^{3}z  }= \\ =3 a^{2}b ^{3}c^{5}8^{-1}x ^{-4}y^{-3}z^{-1}
tankabanditka [31]3 years ago
4 0

Answer:

3 * 2^{-3}a^{2}b^{3}c^{5}x^{-4}y^{-3}z

Step-by-step explanation:

you take away 8 and multiply  and get 3a^2b^3c^5 * x^4y^3z or something

This becomes 3a^2b^3c^5x^-4y^-3z/8

Then you move the 8 up using multiplication and get -24a^2b^3c^5x^4y^3z

This can be simplifed as 3*2^-3a^2b^3c^5x^-4y^-3z

regardless that's the real answer.

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I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?
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Given:

In a number, adding 1\dfrac{3}{4}, then multiplying the result by 2\dfrac{2}{11} we get 8.

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Let the unknown number be x.

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