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WINSTONCH [101]
3 years ago
13

Simplify 3a^2b^3c^5 __________________ 8x^4y^3z

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).
\frac{3a ^{2} b ^{3}c ^{5}  }{8 x^{4}y ^{3}z  }= \\ =3 a^{2}b ^{3}c^{5}8^{-1}x ^{-4}y^{-3}z^{-1}
tankabanditka [31]3 years ago
4 0

Answer:

3 * 2^{-3}a^{2}b^{3}c^{5}x^{-4}y^{-3}z

Step-by-step explanation:

you take away 8 and multiply  and get 3a^2b^3c^5 * x^4y^3z or something

This becomes 3a^2b^3c^5x^-4y^-3z/8

Then you move the 8 up using multiplication and get -24a^2b^3c^5x^4y^3z

This can be simplifed as 3*2^-3a^2b^3c^5x^-4y^-3z

regardless that's the real answer.

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Graph the function f(x) = (x + 1)(x - 5). Use the drop-
hodyreva [135]

Answer:

3) (2,-9)

4) (0,-5)

5) (1,-8)

Step-by-step explanation:

3)

The vertex will occur between you x-intercepts.

You already found that happens at x=2.

To find the corresponding y-coordinate, replace x in

f(x)=(x+1)(x-5) with 2:

f(2)=(2+1)(2-5)

f(2)=(3)(-3)

f(2)=-9

So the vertex is (2,-9).

4)

The y-intercept is when x=0.

So in f(x)=(x+1)(x-5) replace x with 0:

f(0)=(0+1)(0-5)

f(0)=(1)(-5)

f(0)=-5

So the y-intercept is (0,-5).

5)

To find another point just plug in anything besides any x already used.

We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.

So replace x in f(x)=(x+1)(x-5) with x=1:

f(1)=(1+1)(1-5)

f(1)=(2)(-4)

f(1)=-8

So another point to graph is (1,-8).

7 0
3 years ago
At a bus station, buses begin their routes at 6 a.M. The schedule for two of the buses is based on the time intervals listed bel
Marianna [84]

Answer:

The next time both will leave the bus station at the same time is 7:15 a.m.

Step-by-step explanation:

Since 15 and 75 are multiples to each other.

So, L.C.M. of 15 and 75 is 75.

So, after 75 minutes both buses will leave the station at the same time.

Also since buses begin their routes at 6 a.m.

So, next time they will meet at

6 hours 0 minutes + 75 minutes = 7 hours 15 minutes = 7:15 a.m.

7 0
3 years ago
There are 4040 tables in a library, with 30%30% of them seating 44 people. The tables remaining only seat 22 people. How many se
vaieri [72.5K]
The answer is 58!!!!!!!!
8 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
15x+12=45+4x<br> whats x?
saul85 [17]

<span>15x+12=45+4x </span>⇒15x - 4x = 45 - 12 ⇒ 11x = 33 ⇒ x = 3


4 0
3 years ago
Read 2 more answers
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