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WINSTONCH [101]
3 years ago
13

Simplify 3a^2b^3c^5 __________________ 8x^4y^3z

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).
\frac{3a ^{2} b ^{3}c ^{5}  }{8 x^{4}y ^{3}z  }= \\ =3 a^{2}b ^{3}c^{5}8^{-1}x ^{-4}y^{-3}z^{-1}
tankabanditka [31]3 years ago
4 0

Answer:

3 * 2^{-3}a^{2}b^{3}c^{5}x^{-4}y^{-3}z

Step-by-step explanation:

you take away 8 and multiply  and get 3a^2b^3c^5 * x^4y^3z or something

This becomes 3a^2b^3c^5x^-4y^-3z/8

Then you move the 8 up using multiplication and get -24a^2b^3c^5x^4y^3z

This can be simplifed as 3*2^-3a^2b^3c^5x^-4y^-3z

regardless that's the real answer.

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2 years ago
Pls help! simple question will give brainliest!
Sphinxa [80]

Answer:

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3 years ago
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Solve each quadratic equation. Show your work. 14. (2x – 1)(x + 7) = 0 15. x2 + 3x = 10 16. 4x2 = 100
andreyandreev [35.5K]
14.  (2x - 1)(x + 7) = 0

Using the zero factor property, we know that either the first or second terms (or both) must be equal to 0 if their product is 0.  We can set each term equal to 0 to find the solutions:

2x - 1 = 0
2x = 1
x = 1/2

x + 7 = 0
x = -7

15.  x^{2} +3x=10

To solve this equation, you first need to set it equal to 0:

x^{2} +3x=10 \\ x^{2} +3x-10 = 0

Next, it can be factored:

x^{2} +3x-10 = 0 \\ (x+5)(x-2)=0

Finally, we can solve just like we did above:

x + 5 = 0
x = -5

x - 2 = 0
x = 2

16.  4x^2=100

First, you can simplify by dividing each side by 4:

4x^2=100 \\ x^2=25

Now, set the equation equal to 0:

x^2=25 \\ x^2-25=0

Next, factor:

x^2-25=0 \\ (x+5)(x-5)=0

Finally, find the solutions:

x + 5 = 0
x = -5

x - 5 = 0
x = 5
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3 years ago
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Answer:

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6 0
3 years ago
What is the solution to 3/4b=8
soldier1979 [14.2K]

Answer:

b=\frac{32}{3}

Step-by-step explanation:

\frac{3}{4}b=8

Multiply both sides by 4:

4\times \frac{3}{4}b=8\times4

3b=32

Divide both sides by 3:

\frac{3b}{3}=\frac{32}{3}

b=\frac{32}{3}

6 0
3 years ago
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