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serg [7]
3 years ago
5

If anyone can help me that would be great

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

30+[10+(3²-4)]

30+[10+(9-4)]

30+[10+5]

30+15

45

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A 3” x 5” photo is enlarged so that the length of the new photo is 7 inches. Find the width of the new photo.. a. 4.20 inches. c
Andrej [43]
As far as the old dimensions of the photo are concerned,
Width of the photo = 3"
Length of the photo = 5"
New length of the photo = 7 inches
Let us assume the new width of the photo = x inches
Then
3/5 = x/7
5x = 7 * 3
5x = 21
x = 21/5
   = 4.20 inches
So the correct option among all the options that are given in the question is the first option. I hope that the answer has come to your help.
3 0
3 years ago
What would be the answer ?
Blizzard [7]

Answer: $13

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
How do you solve 3^(4x) = 3^(5-x)?
trasher [3.6K]
3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1
3 0
3 years ago
If you could do this you’re the best and you’ll also get a lot of points thanks
Andre45 [30]

Answer:

take the answer on picture which I attached with your question

3 0
3 years ago
Which is the value of this expression when a=5 and k=-2
Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

(\frac{3^2a^{-2}}{3a^{-1}})^k

The value of a =5 and k = -2

Putting the values and solving

=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}

Option C is correct.

3 0
3 years ago
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