The answer to your question would be 6!
Answer:
a) y =2/3 x + 7.
b) x = -1
c) y = -4/5 x - 1/5
d) y = -3/2 x + 5/2.
Step-by-step explanation:
a) Intercept form y = mx + b where m = 2/3 and b = 7
b) y can take any value but x is always -1.
c) Slope m = (-1-3)/ (1 - -4)
= -4/5
Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:
y - y1 = m(x - x1)
y - -1 = -4/5(x - 1)
y + 1 = -4/5x + 4/5
y = -4/5 x - 1/5
d) The slope m of the line perpendicular to this line is:
-1 / 2/3
m = -3/2.
When x = -1 , y = 4 so using the slope intercept form of a line
y = mx + b
4 = -3/2 * -1 + b where b = the y-intercept.
4 = 3/2 + b
b = 4 - 3/2 = 5/2.
The equation is y = -3/2 x + 5/2.
sorry ill give points back
it's this tally/nathan?
9514 1404 393
Answer:
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.