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Fantom [35]
3 years ago
11

liam is planting 30 bean plants and 45 pea plants in his garden. if he puts the same number of plants in each row and if each ro

w has only one type of plant, what is the greatest number of plants he can put in one row?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0
No it is 2109 plus 3829= 21
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F(x) = |x|; Find f(8)
Valentin [98]
<h2><u>Answer:</u></h2>

8

<h2><u>Step-by-step explanation:</u></h2>

<u />

Replace the x with 8.

The absolute value makes any number positive.

Since 8 is already positive, there is no change in the answer.

f(8) = 8

7 0
3 years ago
Find a formula for the arithmetic sequence consisting of the positive multiples of 4
GarryVolchara [31]

9514 1404 393

Answer:

  4n

Step-by-step explanation:

For positive multiple number 'n', the value is 4n.

  a[n] = 4n . . . . . where a[n] is the n-th term of the sequence

8 0
3 years ago
Find three consecutive odd integers so that the product of the second and third integer is 63
Doss [256]
<span>product of the second and third integer is 63
63=3*3*7
or
63=7*9 These are two consecutive integers.
We need three integers and the first one is missing so the solution:
5-7-9

</span>
4 0
3 years ago
Answer this if you want to be the brain list master ​
mojhsa [17]

Answer:

3,240 / 9= 360\

360 boxes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

7 0
2 years ago
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