Answer:
12 with a remainder of 5
Step-by-step explanation:
have a good day! :)
First we need to get x
<RNA = <ENV [v.o.a]
8x+12=5x+57
8x-5x=57-12
3x=45
x=15
<ENV= (5×15+57)
<ENV =132
the answer is D
Reduce the expression, if possible, by canceling the common factors.
Exact Form: 22/15
Decimal Form: 1.46
Mixed Number Form: 1/715
Answer:
C
Step-by-step explanation:
related equation
-16t^2 + 32t + 20 = 0
-4t^2 + 8t + 5 = 0
Δ/4 = 16 + 20 = 36
t1 = (-4 + 6)/-4 = -1/2
t2 = (-4 - 6)/-4 = 5/2
-16(t+1/2)(t-5/2)
-16(2t+1/2)(2t-5/2)
-4(2t+1)(2t-5)
Since the equation is A= 1/2 times base times height, I did the base as 8 and the height as 5.
