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Sphinxa [80]
3 years ago
15

The roof of a home rises vertically at a distance of 8 ft through a horizontal distance of 15 ft. Find the pitch (slope) of the

roof.
The first person to answer correctly gets 25 points and brsinlyest.
Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
Answer: 18/15
Hope it’s help you
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Graph quadrilateral ABCD and find the most precise name (square, rectangle,
Pavlova-9 [17]

Answer:

Kite

Step-by-step explanation:

To graph quadrilateral with points:

A(-1,-2)

B(5,1)

C(-3,1)

D(-1,4)

Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:

Measure of segment AB= Measure of segment BD = 6.708 units

Measure of segment AC= Measure of segment CD = 3.605 units

Thus, adjacent pair of sides of the quadrilateral are congruent.

Major diagonal BC cuts the minor diagonal AD at point E such that:

Measure of segment AE= Measure of segment ED = 3 units

m∠AEB = m∠DEB = 90°

Thus, major diagonal is a perpendicular bisector of the minor diagonal.

The above stated features fulfills the criterion of a kite.

Hence, the given quadrilateral ABCD is a kite.

8 0
3 years ago
Solve the equation x2 + x = 12.
Otrada [13]

please give brainliest

Let's solve your equation step-by-step.

x2+x=12

Step 1: Subtract 12 from both sides.

x2+x−12=12−12

x2+x−12=0

Step 2: Factor left side of equation.

(x−3)(x+4)=0

Step 3: Set factors equal to 0.

x−3=0 or x+4=0

x=3 or x=−4

Answer:

x=3 or x=−4

3 0
2 years ago
Read 2 more answers
How does difference of squares work?
kodGreya [7K]

Every difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results. Step 3: Determine if the remaining factors can be factored any further.

6 0
3 years ago
(1+tan^2 A)cot A/cosec^2 A= tanA​
Rufina [12.5K]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

1 + tan²A = sec²A , secA = \frac{1}{cosA}, cosecA = \frac{1}{sinA} , cotA = \frac{cosA}{sinA} , tanA = \frac{sinA}{cosA}

Consider the left side

\frac{(1+tan^2A)cotA}{cosec^2A}

= \frac{sec^2AcotA}{cosec^2A}

= \frac{\frac{1}{cos^2A}(\frac{cosA}{sinA})  }{cosec^2A}

= \frac{\frac{1}{cosAsinA} }{\frac{1}{sin^2A} }

= \frac{1}{cosAsinA} × sin²A

= \frac{sinA}{cosA}

= tanA = right side , thus proven

4 0
3 years ago
Eve bought 6 3/4 pounds of clay for her sculpting project. She separated the clay into equal pieces that each weighed 1 1/8 poun
ValentinkaMS [17]
Sorry I can't help with the formula to work it into simplest form but the answer is 6 pieces of clay :(
6 0
3 years ago
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