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Lelechka [254]
3 years ago
9

Answer with solutions thank you

Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

{ \tt{ \frac{8}{ {b}^{2}  - 4} . \frac{b - 2}{2b + 4} \div  \frac{4}{2 {(b + 2)}^{2} }  }} \\  \\  = { \tt{ \frac{8}{(b - 2)(b + 2)} \times  \frac{b - 2}{2b + 4}   \div  \frac{4}{2 {(b + 2)}^{2} } }} \\  \\  = { \tt{ \frac{8}{b + 2}  \times  \frac{1}{2b + 4}  \times  \frac{2(b + 2) {}^{2} }{4} }} \\  \\  = { \tt{ \frac{8}{2b + 4}  \times  \frac{2b + 4}{4} }} \\  \\  = { \tt{ \frac{8}{4} }} \\  \\  = { \underline{ \tt{ \: 2 \: }}}

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