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Lelechka [254]
3 years ago
9

Answer with solutions thank you

Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

Answer:

{ \tt{ \frac{8}{ {b}^{2}  - 4} . \frac{b - 2}{2b + 4} \div  \frac{4}{2 {(b + 2)}^{2} }  }} \\  \\  = { \tt{ \frac{8}{(b - 2)(b + 2)} \times  \frac{b - 2}{2b + 4}   \div  \frac{4}{2 {(b + 2)}^{2} } }} \\  \\  = { \tt{ \frac{8}{b + 2}  \times  \frac{1}{2b + 4}  \times  \frac{2(b + 2) {}^{2} }{4} }} \\  \\  = { \tt{ \frac{8}{2b + 4}  \times  \frac{2b + 4}{4} }} \\  \\  = { \tt{ \frac{8}{4} }} \\  \\  = { \underline{ \tt{ \: 2 \: }}}

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Can someone answer 15b
NISA [10]
A)

well, we know the elevator's rate is -20 f/s, ok, so every second, is dropping 20 feet, therefore, "y" is "distance from the ground floor", so when y = 0, meaning the distance to the ground floor is 0, so you ARE at the ground floor then.

and "x" is how many seconds you've been in the elevator.

now, she got in the elevator for 6 seconds, so, the elevator went down by 20 * 6, or 120 feet down, reason why the slope is negative, when she stopped, she was 350 feet away from the ground floor still though.

if the elevator went down 120 feet, and she's still 350 feet from the ground floor, that means  she boarded the elevator at 120 + 350 feet, or 470 feet.

b)

\bf \begin{array}{lcccllll}
&\stackrel{\textit{elapsed seconds}}{x_1}&\stackrel{\textit{ft from ground-floor}}{y_1}\\
%   (a,b)
&({{ 6}}\quad ,&{{ 350}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies -20
\\\\\\
% point-slope intercept
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\\\\\\
y-350=-20x+120\implies  y=-20x+\stackrel{y-intercept}{470}
6 0
3 years ago
In​ Marissa's calculus​ course, attendance counts for 15​% of the​ grade, quizzes count for 20​% of the​ grade, exams count for
Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

Attendance counts for 15% of the grade and she has 100% average on that. So we have:

attendance = weight*(Marissa's average)

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Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

Quizzes = 20%*(93/100) = 18.6 %

Exams counts for 50% of the grade and she has a 82% average on that. So we have:

Exams = weigth*(Marissa's average)

Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

Finals = 15%*(85/100) = 12.75%

So her grade is the sum of all the cattegories:

Course's average = 15+18.6+41+12.75 = 87.35 %

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