Answer:
The support is 41 inches long.
Step-by-step explanation:
There's two ways we can do this: one with the diagonal formula and one without.
Since we know that Point C is halfway down leg A and that the table legs are 18 inches tall, Point C is 9 inches down leg A. The support, from Point C to Point D, will form a diagonal, the length of which we need to find. We know from the diagram that the width of the table is 24 inches and that its length is 32 inches. We have a height, length, and width for this problem, so let's imagine a rectangular prism, which has all three of those things, instead of a table. The formula for finding a rectangular prism's diagonal is
. Let's put in those numbers:

Therefore, the support is 41 inches long.
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Another way you can do this is to use the Pythagorean Theorem twice: once to find the diagonal of the tabletop and another time for the support.

Now that we know the corner-to-corner distance for the tabletop, we'll use that and the 9 inch distance for Point C to find the distance between C and D:

Again, the support is 41 inches long.
<h2>
Answer: <em><u>
Less Than</u></em></h2>
Step-by-step explanation: 7^2 = 49, but 3^4 = 81. 49 < 81
Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.
Now, Pythagoras' Theorem is defined as follows:
c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:
c^2 = a^2 + b^2
24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)
b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)
b = √(24^2 - 8^2) (Take the square root of both sides)
b = √512 (Evaluate 24^2 - 8^2)
b = 16√2 (Simplify √512)
= 22.627 (to three decimal places)
I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.
Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2
Answer:
1)0.123( bar on 3)
Let X = 0.123 ( bar on 3)
Then X = 0.1233 --------(1)
Multiply equation (1) by 100 we get,
100X = 12.33 --------(2)
Again multiply equation (2) by 10 we get,
1000X = 123.33 -------(3)
Subtract equation (2) from equation (3) we get,
1000X = 123.33
100X = 12.33
____________
900X = 111
X = 111/900
Hence,
0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.