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3 years ago

Write an expression that is equivalent to the following expression by factoring out the GCF 16y+18m

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Answer:

2(8y+9m)

Step-by-step explanation:

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What is X and how do I find it??

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Answer:

x ≈ 10.92

Step-by-step explanation:

Using the sine ratio in the right triangle

sin83° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{11}$

Multiply both sides by 11

11 × sin83° = x, thus

x ≈ 10.92 ( to 2 dec. places )

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3 years ago

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Sin= opp/hyp
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Answer: 2nd choice

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3 years ago

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Answer:I can’t I sorry I don’t know this question

Step-by-step explanation:

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3 years ago

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio

Maksim231197 [3]

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t years, $P_{0}$ is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that $P_{0} = 1.65, P(3) = 1.74$

Applying this to the equation, we find r. So

$P(t) = P_{0}e^{rt}$

$1.74 = 1.65e^{3r}$

$e^{3r} = \frac{1.74}{1.65}$

$e^{3r} = 1.0545$

Applying ln to both sides

$\ln{e^{3r}} = \ln{1.0545}$

$3r = \ln{1.0545}$

$r = \frac{\ln{1.0545}}{3}$

$r = 0.0177$

$P(t) = 1.65e^{0.0177t}$

What would be the population of the city 5 years after the start of the population study?

This is P(5).

$P(t) = 1.65e^{0.0177t}$

$P(5) = 1.65e^{0.0177*5}$

$P(5) = 1.8027$

So the correct answer is:

C. 1.8027

6 0

3 years ago