You are given two equations, solve for one variable in one of the equations. Say you solved for x in the second equation. Then, plug in that value of x in the x of the first equation. Solve this (first) equation for y (as it should become apparent) and you'll get a number value. Plug in this numerical value of y into the y of the second equation. Solve for x in the second equation. And there you have it: (x, y)
I have to interpret that:
1) the smaller square has side length = 3 cm
2) the bigger square has side length = 5 cm
3) the smaller square is completely inside the bigger square.
4) the points cannot be outside the bigger square
Under those assumptions the probability that a point is inside the smaller square is
P (inside the smaller square) = area of the smaller square / area of the bigger square
P (inside the smaller squere) = (3cm)^2 / (5cm)^2 = 9 / 25
Answer: 9 / 25
After a little manipulation, the given diff'l equation will look like this:
e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2
Now let x=0 and y = 1, o find c:
e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.
Answer:
Step-by-step explanation:
a=3
b=-5
c=2
Answer:
Hello,
In order to determine which is the horizontal asymptote remember that the horizontal is always x= something and remember that horizontal is straight from left to right.
So Horizontal asymptote = 2
For vertical asymptote it goes from the bottom of the graph, directly up. Think about it like this, you stand upright...or vertically right? So the vertical asymptote is
y= 0
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