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Bond [772]
2 years ago
11

What is the range of the given function ?

Mathematics
2 answers:
sveta [45]2 years ago
6 0

Answer:

6740

Step-by-step explanation:

-BARSIC- [3]2 years ago
4 0

Answer:

There is no function provided

FYI

Domian is all x-values

range is all y-values

For ex..

(-3,6)

-3 is domain

6 is range

Step-by-step explanation:

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Solve using the quadratic formula.<br> 7q² – 9q- 1=0
Mama L [17]

Answer:Q=1.39 or -0.103

Step-by-step explanation:

6 0
4 years ago
What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.
Anit [1.1K]

The equation of the line is, \rm y = 3x + 1.

Given that,

The equation of the line is,

\rm y = \dfrac{1}{3} x+4\\

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

\rm = \dfrac{1}{3}x + 4\\

On comparing with the standard equation of the line y = mx +c.

The slope of the line m_1 is 1/3.

When two lines are perpendicular the relation between these slopes is,

\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3

And line contains the point (-2, -5).

Then,

\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

\rm y = mx +c \\\\y = 3x +1

Hence, The required equation of the line is, \rm y = 3x + 1.

For more details refer to the link given below.

brainly.com/question/14388443

7 0
3 years ago
It is the middle one <br> And can you plz show work thanks
Ede4ka [16]

Answer:

multiply the length value by 1760

2.4*1760 is 4224

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
As an estimation we are told £3 is €4. <br> Convert €96 to pounds
Maru [420]
96*3/4
288/4
=72 pounds
8 0
3 years ago
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The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr
aniked [119]

Answer:

(a) E(X) =  0.383

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) P(x = 4) = 0.000169

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$ E(X) =  \frac{n \times r}{N} $

$ E(X) =  \frac{10 \times 8}{209} $

$ E(X) =  \frac{80}{209} $

E(X) =  0.383

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$ P(x = 4) =  \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}} $

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$ P(x = 4) =  \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $

$ P(x = 4) =  \frac{70 \times 84944276340}{35216131179263320}

P(x = 4) = 0.000169

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0
3 years ago
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