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3 years ago

Solve for 2x+3y+6z when x=4, y=3, and z=6.

Mathematics

2 answers:

liraira [26]3 years ago

4 0

Answer:

Step-by-step explanation:

substitute values in

2(4) + 3(3) + 6(6) = 8 + 9 + 36 which then equals 53

Alisiya [41]3 years ago

4 0

The answer you are looking for is 53.

Solution/Explanation:

Writing out the expression first

2x+3y+6z

Substituting the given values of the variables

x=4

y=3

z=6

2(4)+3(3)+6(6)

2(4)=8

3(3)=9

6(6)=36

You will come up with 8+9+36.

From this, you will get 53.

So, therefore, the final answer to this problem is 53.

Hope this helped answer your question for you. Good day to you.

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Been struggling with this question for an hour :( please give simple explanation! thank you

Orlov [11]

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6 0

3 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

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7 0

3 years ago

What is the domain and range?

Viefleur [7K]

Answer:

Domain is your x max and Min, Range is your y max and Min

Step-by-step explanation:

Domain would be -5 to 8 or (-5,8)

range would be -3 to 2 or (-3,2)