Answer:
Explanation:
The area of the <em>octagon</em> may be calculated as the difference of the area of the original square and the area of the four corners cut off.
1) <u>Area of the square</u>.
The original square's side length is the same wide of the formed octagon: 10 cm.
So, the area of such square is: (10 cm)² = 100 cm².
2) <u>Area of the four corners cut off</u>.
Since, the corners were cut off two centimeters from each corner, the form of each piece is an isosceles right triangle with legs of 2 cm.
The area of each right triangle is half the product of the legs (because one leg is the base and the other leg is the height of the triangle).
Then, area of one right triangle: (1/2) × 2cm × 2cm = 2 cm².
Since, they are four pieces, the total cut off area is: 4 × 2 cm² = 8 cm².
3) <u>Area of the octagon</u>:
- Area of the square - area of the cut off triangles = 100 cm² - 8cm² = 92 cm².
And that is the answer: 92 cm².
The value of <em>x</em> where by exterior angles theorem, ∠DCO equals 2·x, 69° equals the sum of ∠DCO and x° is <em>x </em>= 23°
<h3>What is the exterior angles theorem?</h3>
The exterior angles theorem states that the exterior angle of a triangle is equal to the sum of the opposite interior angles.
The given parameters are;
Points on the circle are; ABCD
Straight lines = AOBE and DCE
Segment CO = Segment CE
∠AOD = 69°
∠CEO = x°
∠OCD = ∠ODC base angles of isosceles triangle
69° = ∠x° + ∠ODC exterior angle of a triangle
∠DOC = 180 - 2×∠ODC (Angle sum property of a triangle)
180 - 2×∠ODC + x° + 69° = 180° (Sum of angles on a straight line are supplementary)
x° + 69° - 2×∠ODC = 0
∠ODC = 2·x° (exterior angle of a triangle is equal to the sum of the opposite interior angles)
69° = x° + ∠ODC = x° + 2·x° = 3·x° (substitution property of equality)
69° = 3·x°
x = 69° ÷ 3 = 23°
Learn more about angles in a triangle here:
brainly.com/question/25215131
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Clam down jamal don't pull out the 9 X_X
Step-by-step explanation:
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Step-by-step explanation:
How much is a pound/lb? Then do 5.17 divided by (however much is a pound/lb)
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