Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Answer:
B: 43.3
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
3x+11=5x+100
move terms
3x-5x=100-112
subtract 3x to 5x and subtract 100 to 112
-2x=-12
divide both sides by -2
x=6
Answer:
27.56 cm
Step-by-step explanation:
→ Identify the multiplier
( 100 + 6 ) ÷ 100 = 1.06
→ Multiply by the length
26 × 1.06 = 27.56
Answer:
The last one
Step-by-step explanation:
