Answer:
Domain → 0 < x < 5
Step-by-step explanation:
Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)
Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)
So the input values of the table (Number of shirts sold) will represent the domain of the linear function.
Hence, reasonable domain for the function will be → 0 < x < 5
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
The answer is 36
Step-by-step explanation:
- First you have to divide 288 by 8 and
- then you have to see how many times 8 will go into 2 it can't so see how many times it will go into 28 which is 3 and you will get 24
- then you subtract 24 from 28 and you get 4
- then bring down the 8 an it 48 now see how many times 8 will go into 48 which is 6 times and you get 48
- then you subtract 48 by 48 and you get 0 so the answer is 36
- HOPE THIS HELPED
Answer:
Reflect and compress
Step-by-step explanation: