Answer:
12.2
Step-by-step explanation:
Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
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The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
In this question, we have to use the intersecting chord theorem, and the formula which is
In the given circle, values of AP, CP and DP are 12m, 6m and 5m respectively .
Substituting the values in the formula, we will get
Dividing both sides by 5
(32600/100) x 5 = 1630
32600+1630= 34230$
