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3 years ago

16 + 4x + 2x-3x + x = 0

2 answers:

4 0

16 + 4x + 2x - 3x + x = 0

First, simplify 16 + 4x + 2x - 3x + x to get 16 + 4x. / Your problem should look like: 16 + 4x = 0
Second, subtract 16 from both sides. / Your problem should look like: 4x = -16
Third, divide both sides by 4. / Your problem should look like: x = $-\frac{16}{4}$
Fourth, simplify $\frac{16}{4}$ to get 4. / Your problem should look like: x = -4

Answer: x = -4

nekit [7.7K]3 years ago

4 0

16+4x+2x−3x+x=0

Simplify:

16+4x+2x−3x+x=0

16+4x+2x+−3x+x=0

(4x+2x+−3x+x)+(16)=0(Combine Like Terms)

4x+16=0

Subtract 16 from both sides.

4x+16−16=0−16

4x=−16

Divide both sides by 4.

4x/4=−16/4

x=−4

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(1) Write the ratio of the volumes of the 500ml bottle and the 2-litre bottle of milk in its simplest form.

Vadim26 [7]

Answer:

1] 1 : 4

2] 250ml

Step-by-step explanation:

1] 500ml : 2 litre

First, the units must be the same.

2 litre = 2000ml

500ml : 2000ml

5 : 20

1 : 4

2] $\frac{2}{4}$ × 500

= 250ml

8 0

3 years ago

A set of computer science exam scores are normally distributed with a mean of 71.33 point, and a standard deviation of 3 points.

Bess [88]

Answer: 0.86 of the exam scores are between 68 and 77.99 points

Step-by-step explanation:

Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = computer science exam scores .

µ = mean score

σ = standard deviation

From the information given,

µ = 71.33 points

σ = 3 points

We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as

P(68 ≤ x ≤ 77.99)

For x = 68,

z = (68 - 71.33)/3 = - 1.11

Looking at the normal distribution table, the probability corresponding to the z score is 0.13

For x = 68,

z = (77.99 - 71.33)/3 = 2.22

Looking at the normal distribution table, the probability corresponding to the z score is 0.99

P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86

5 0

3 years ago

What is (2a^3 b^4 c^3)^2 • (4a^2 bc^3)

Free_Kalibri [48]

Answer:16 a 8 9 c 9

Step-by-step explanation:

5 0

3 years ago

In Pant Science (May 2010), a group of Japanese environmental scientists investigated the ability of a hybrid tomato plant to pr

Neporo4naja [7]

Answer:

a) P(x > 120) = 0.03288

b) P(100 < x < 110) = 0.46777

c) value of a for which P(x < a) = 0.25

a = 99.91

Step-by-step explanation:

This is a normal distribution problem with

Mean = μ = 105.3

Standard deviation = σ = 8.0

a) P(x > 120)

To work this, we first need To convert 120 go standardized/normalized/z-scores.

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (120 - 105.3)/8.0 = 1.84

To determine P(x > 120) = P(z > 1.84)

We use the tables for these probabilities now.

P(x > 120) = P(z > 1.84) = 1 - P(z ≤ 1.84) = 1 - 0.96712 = 0.03288

b) P(100 < x < 110)

We normalize the two value in the inequality

For 100,

z = (x - μ)/σ = (100 - 105.3)/8.0 = -0.66

For 110,

z = (x - μ)/σ = (110 - 105.3)/8.0 = 0.59

To determine P(100 < x < 110) = P(-0.66 < z < 0.59)

We use the tables for these probabilities now.

P(100 < x < 110) = P(-0.66 < z < 0.59) = P(z < 0.59) - P(z < -0.66) = 0.72240 - 0.25463 = 0.46777

c) value of a for which P(x < a) = .25

Let the z-score of a be z'

z' = (x - μ)/σ = (a - 105.3)/8.0

P(x < a) = P(z < z') = 0.25

Using the table, z' = - 0.674

-0.674 = (a - 105.3)/8

a - 105.3 = -5.392

a = 105.3 - 5.392 = 99.91

Hope this Helps!!!

5 0

3 years ago

Which set of numbers shows the lower extreme, the lower quartile, the median, the upper quartile, and the upper

kumpel [21]

B: (6,12,18,44,54)

I just did this and this was correct.

8 0

3 years ago