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disa [49]
3 years ago
13

16 + 4x + 2x-3x + x = 0

Mathematics
2 answers:
NemiM [27]3 years ago
4 0
16 + 4x + 2x - 3x + x = 0

First, simplify 16 + 4x + 2x - 3x + x to get 16 + 4x. / Your problem should look like: 16 + 4x = 0
Second, subtract 16 from both sides. / Your problem should look like: 4x = -16
Third, divide both sides by 4. / Your problem should look like: x = -\frac{16}{4}
Fourth, simplify \frac{16}{4} to get 4. / Your problem should look like: x = -4

Answer: x = -4

nekit [7.7K]3 years ago
4 0


16+4x+2x−3x+x=0

Simplify:

16+4x+2x−3x+x=0

16+4x+2x+−3x+x=0

(4x+2x+−3x+x)+(16)=0(Combine Like Terms)


4x+16=0

Subtract 16 from both sides.

4x+16−16=0−16

4x=−16

Divide both sides by 4.

4x/4=−16/4

x=−4

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Answer:

Your(my) number is 40

Step-by-step explanation:

I. Given 80/something, + 13, * 5 = 75 when x is something

So [  \frac{80}{x} + 13 ]5 = 75

     [ \frac{400}{x} + 65] = 75

     \frac{400}{x} = 75 - 65

     \frac{400}{x}  = 10

     400 = 10x

        x = 40

II. Prove by replace 40 in x

    [(80/40) + 13]5 = 75

    [2 + 13] 5 = 75

    (15)5 = 75

        75 = 75 true

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