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mojhsa [17]
3 years ago
10

If p(x) = 5(x2 + 1) + 16, what is the value of p(11)?

Mathematics
2 answers:
Afina-wow [57]3 years ago
7 0

Answer:

{ \rm{p(x) = 5( {x}^{2} + 1) + 16  }} \\

• If they ask value of p(11), substitute x with 11:

{ \rm{p(11) = 5( {11}^{2}  + 1) + 16}} \\  \\ { \rm{p(11) = 610 + 16}} \\  \\ { \boxed{ \boxed{ \rm{p(11) = 626}}}}

Vilka [71]3 years ago
4 0

Answer:

131

Step-by-step explanation:

P(11) = 5(2(11) + 1) + 16

p(11) = 5(22 + 1) + 16

p(11) = 5(23) + 16

p(11) = 115 + 16

p(11) = 131

Hope this helps! Pls give brainliest!

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Answer:

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Step-by-step explanation:

Steps

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$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

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Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

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