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olga nikolaevna [1]
3 years ago
5

Solve for theta to the nearest degree​

Mathematics
1 answer:
ozzi3 years ago
6 0

Step-by-step explanation:

So first thing is to determine which trigonometric ratio we use here. Theta is adjacent to 5 and 8 is the hypotenuse, so we should be using Cosine.

So we set up the equation

cos θ = adj/hype

cos θ = 5/8

θ = cos^{-1} (5/8)

θ=51.3178125...

θ=51°

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Answer choice (A)5/30 (B)3/17 (C) 8/30 (D) 16/30
ratelena [41]
<h3>Answer: (C) 8/30</h3>

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Explanation:

There are 5+3 = 8 people in choir and running club. I added the values in the overlapped region of the circles "choir" and "running club".

This is out of 2+5+6+7+3+4+3 = 30 people total.

Divide the two results to form the fraction 8/30

Ideally we should reduce to get 4/15, but your teacher has chosen not to reduce.

8 0
3 years ago
The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
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2 step: T_{n}=T_{1}*q^{n-1}, then 
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and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

3 step: Solve this system  \left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right. and dividing first equation on second we obtain \frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}. So, \frac{(q-1)(q+1)}{q+1} = \frac{1}{2} and q-1= \frac{1}{2}, q= \frac{3}{2} - the common ratio.

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3 years ago
You are selling tickets for a high school basketball game. Student tickets cost $3 and general admission tickets cost $5. You se
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Answer:

5 stars? Answer down below

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40 x (80/100)
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