Answer:
8% probability that he or she actually has the disease
Step-by-step explanation:
We use the Bayes Theorem to solve this question.
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?
This means that:
Event A: Test comes back positive.
Event B: Having the disease.
Test coming back positive:
2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that 
For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.
Then
Finally:
8% probability that he or she actually has the disease
Remember, you can do anything to an equationas long as you do it to both sides
1.
-6+x=-3
add 6 to both sides
6-6+x=6-3
0+x=3
x=3
2.
add like terms
-5a+5a+9=8
0a+9=8
0+9=8
9=8
false
no solution
zero solutions
Answer:
x=17
Step-by-step explanation:
7x+15=4x+66
3x=51
x=17
Answer:
Step-by-step explanation: base x height
70ft
Answer:
The values of a and b are:
Step-by-step explanation:
We know that the slope-intercept form of the line equation
y = ax+b
where
From the diagram of the line graph, we can fetch the two points
Determining the slope between (0, 2) and (-1, 0)
Thus, the value of a = 2
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
From the graph, it is clear
at x = 0, y = 2
Thus, the y-intercept b = 2
now substituting a = 2 and b = 2 in the slope-intercept form of the line equation
y = ax+b
y = 2x + 2 ∵ a = 2 , b = 2
Thus, the line of equation is:
y = 2x+2
now comparing with y = ax+b
Here:
a = 2
b = 2
Therefore, the values of a and b are:
