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jolli1 [7]
3 years ago
10

Solve 31-X + (2 x + 1)] = x - 1.

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)

Step-by-step explanation:

31 - X + (2x+1) = x - 1

or, 2x+1 = x - 1 - 31 + X

or, 2x - x = -1 -31 + X -1

or, x = -2 -31 + X

or, x = X - 33

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expeople1 [14]

Answer:

-3x+6y=42

-3x+6y-42=0

-x+2y-14=0

x-2y+14=0

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Rina8888 [55]

x^2-x-12=x^2+3x-4x-12=x(x+3)-4(x+3)=(x+3)(x-4)\\\\x^2-2x-8=x^2+2x-4x-8=x(x+2)-4(x+2)=(x+2)(x-4)\\\\4x^2=2x\cdot2x



\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}

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4 years ago
I WILL GIVE BRAINLIEST! PLEASE HELP ME!
PilotLPTM [1.2K]

needless to say that the conversion from miles to kilometers uses a constant value, and therefore, they're directly proportional.

now, I could write the direct proportional relation blah blah but there's no need, we can simply squeeze it out of the table by simply checking how many kilometers there are in 1 mile.

well, we know that 11.0 miles give us 17.699 km, ok hmmm if we divide 17.699 ÷ 11 = 1.609.

if we do the same on table for 26 and 41.834, so 41.834 ÷ 26 = 1.609, and the next pair 54.706 ÷ 34 = 1.609, the value of 1.609 is consistent or constant, or namely that there are 1.609 kilometers in 1 mile.

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X + 6 = -50<br><br> ASAP <br><br> Please!!!!!!!!!
sergejj [24]

Hi there!

Answer:

<u><em>x=-56 and -56=x</em></u>

Step-by-step explanation:

addition property of equality is adding the same number both sides of an equation does not change the equation.

subtraction property of equality is subtraction the same number from both sides of an equation does not change the equation.

subtract by 6 both sides of an equation.

x+6-6=-50-6

simplify.

-50-6=-56

50+6=56

56-6=50

x=-56 and -56=x

Hope this helps!

-Charlie

Have a great day!

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We need more information if we were to help :)

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