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3 years ago

Write an equation of the line passing through the point A(8, 2) that is perpendicular to the line y = 4x−7.

Mathematics

1 answer:

Kay [80]3 years ago

4 0

Answer:

y = - 1/4 + 4

Step-by-step explanation:

y = 4x - 7

Slope = 4

Slope of the perpendicular line = -1/4

Point (8,2)

(b) y-intercept: 2 - (-1/4)(8)

= 2 + 2 = 4

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sally has 200$ in her checking account and gets paid 15$ an hour for babysitting kent has $245 in his checking account and gets

kogti [31]

Answer:

Sally and Kent would have to each work a total of 15 hours to have the same amount of money in their checking account.

Step-by-step explanation:

Set up equations.

x = hours, T = total $

Sally:

T = 200 + 15x

Kent:

T = 245 + 12x

Set both equations equal to each other.

200 + 15x = 245 + 12x (subtract 200 from both sides)

15x = 45 + 12x (subtract 12x from both sides)

3x = 45 (divide both sides by 3)

x = 15

7 0

3 years ago

Brandon made $38.00 in 3 hours. How much would he make in 10 hours

Bad White [126]

Answer:

He would make $126.70 in 10 hours.

Step-by-step explanation:

First, you have to find the unit rate, in other words, how much money he earns in one hour. To do that, you have to divide.

38.00÷3= 12.666667

Once you know how much money Brandon earns in one hour($12.67), you multiply that number by 10.

12.67×10= 126.70

In conclusion, the answer to this solution($126.70) is how much money he earns in 10 hours.

3 0

3 years ago

Read 2 more answers

Greg withdrew $37 from his account on Wednesday and then deposited $15 in his account on Thursday. On Friday, he withdrew $120.

barxatty [35]

he had $297 in his account before wednesday

5 0

3 years ago

3x+2y=0 <br> x-5y=17<br><br> Solving system using elimination

horsena [70]

(2,-3) is the answer

6 0

3 years ago

I have nooooo clue, please help

Aleksandr-060686 [28]

Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

case d) $y^{2}=6x$ ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

3 0

3 years ago