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2 years ago

Write an equation of the line passing through the point A(8, 2) that is perpendicular to the line y = 4x−7.

Mathematics

1 answer:

Kay [80]2 years ago

4 0

Answer:

y = - 1/4 + 4

Step-by-step explanation:

y = 4x - 7

Slope = 4

Slope of the perpendicular line = -1/4

Point (8,2)

(b) y-intercept: 2 - (-1/4)(8)

= 2 + 2 = 4

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Find the slope and y-intercept of the line represented by the table.<br> .<br> Please help me

Brilliant_brown [7]

Step-by-step explanation:

I cant see the question but use the formula

y=mx+b

m=slope

b=y-intercept

you can also use the equation

y2-y1/x2-x1 to find slope.

since its a table, you can plug the x (input) and y (output) coordinates of the table to find the slope.

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Solve 5^3x+1 = 4^x-5 for x

tensa zangetsu [6.8K]

For the equation $5^{3x+1}=4^{x-5}$ take the $\log$ from both sides:

$\log 5^{3x+1}=\log 4^{x-5},\\ \\(3x+1)\log 5=(x-5)\log 4.$

Find x:

$3x\log 5+\log 5=x\log 4-5\log 4,\\ \\3x\log 5-x\log 4=-5\log 4-\log 5,\\ \\x(3\log 5-\log 4)=-5\log 4-\log 5,\\ \\x=\dfrac{-5\log 4-\log 5}{3\log 5-\log 4}=\dfrac{5\log 4+\log 5}{\log 4-3\log 5}.$

Answer: correct choice is D

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KengaRu [80]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Given Equation of line: y=mx+c,

where m = slope of line.

So, we will have to make y the subject to find the slope.

$2x-3y=19\\2x-3y-2x=19-2x\\-3y=-2x+19\\y=\frac{-2x+19}{-3} \\y=\frac{2}{3} x-\frac{19}{3}$

From here, we can see the slope of the line is $\frac{2}{3}$ .

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