The anwser to your question is d
Albert bought 2 pounds of catfish and 2 pounds of salmon
Let c represent the amount of catfish in pounds and s represent the amount of salmon in pounds.
He spent a total of $12 on salmon and catfish and bought a total of 4 pounds. Hence:
c + s = 4 (1)
4c + 2s = 12 (2)
Solving equations 1 and 2 simultaneously gives:
c = 2, s = 2
Albert bought 2 pounds of catfish and 2 pounds of salmon
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Given:
second term = 18
fifth term = 144
The nth term of a geometric sequence is:

Hence, we have:

Divide the expression for the fifth term by the expression for the second term:

Substituting the value of r into any of the expression:

Hence, the explicit rule for the sequence is:
Answer:
1/2
Step-by-step explanation:
output devided by input
Answer:
Step-by-step explanation: