1:equilateral
2:isosceles
3:scalene
4:right
5:acute
6:obtuse
Answer:
4b^-1
Step-by-step explanation:
16a/4 = 4a
4a/a = 4
4/b = 4b^-1
You have to multiply 43 by 17 to get the missing number.
Angle-5 and angle-7 are 'vertical angles', so they're equal,
and we can write ...
<u>10x- 9 = 9x</u>
Subtract 9x from each side: x - 9 = 0
Add 9 to each side: <u> x = 9</u>
Now that we know what 'x' is, we can find the size of Angles-5 and -7 .
Angle-7 = 9x = 81° .
Now look at Angle-6 ... the one that's the answer to the problem.
Angle-6 and -7 together make a straight line, so they must
add up to 180°.
<u>Angle-6 + 81° = 180°</u>
Subtract 81° from each side: Angle-6 = <em>99° .</em>
In Quadrant I, sin(sin^-1(x)) = x.
The appropriate choice is
B.
