Line L1 has gradient 2 and is perpendicular to line L2. Line L2 passes through the point P(2, 1).

Mathematics

1 answer:

Vitek1552 [10]3 years ago

6 0

Answer:

line L1 and line L2 passes L2.

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Center (8,9) and radius r=10

LekaFEV [45]

Answer:

A. Standard form: $(x-8)^2+(y-9)^2=100$

B. General form: $x^2+y^2-16x-18y+45=0$

Step-by-step explanation:

We have been given that center of a circle is at point (8,9) and radius of our circle is 10 units. We are asked to write the equation of our circle.

A. Since we know that the equation of a circle in standard form is: $(x-h)^2+(y-k)^2=r^2$ , where,

(x,y) = Any point on circle,

(h,k) = Center of the circle,

r = Radius of the circle.

Upon substituting our given values in standard form of circle's equation we will get,

$(x-8)^2+(y-9)^2=10^2$

$(x-8)^2+(y-9)^2=100$

Therefore, the equation of our given circle in standard form will be $(x-8)^2+(y-9)^2=100$ .

B. Since we know that equation of a circle in general form is: $x^2+y^2+Ax+By+C=0$ , where, A, B and C are constants.

Upon expanding our standard form of equation we will get,

$x^2-16x+64+y^2-18y+81=100$

$x^2-16x+64+y^2-18y+81-100=100-100$

$x^2-16x+y^2-18y+64+81-100=0$

$x^2-16x+y^2-18y+45=0$

$x^2+y^2-16x-18y+45=0$

Therefore, the equation of our given circle in general form will be $x^2+y^2-16x-18y+45=0$ .

7 0

3 years ago

Please helpppppp !!!

postnew [5]

Answer - 2,500,000 people

8 0

3 years ago

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3/4 divided by 2/3 using fractions

mr_godi [17]

To solve this divition we can write it like:

$\frac{\frac{3}{4}}{\frac{2}{3}}$

So now we can multiplicate the numerator of the first fraction with the denominatior of the second fraction, and put the resould in the numerator of the quationt, ans the same operation for the numeratior with the numerator of the secon fraction and the denominator of the first fraction so: