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Umnica [9.8K]
2 years ago
6

The actual answere 3 + 1(6 ÷ 2)

Mathematics
1 answer:
nadezda [96]2 years ago
4 0

Hey there!

Just do PEMDAS

• Parentheses

• Exponents

• Multiplication

• Division

• Addition

• Subtraction

3 + 1(6 ÷ 2)

= 3 + 1(3)

= 3 + 3

= 6

Therefore, your answer is: 6

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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The line L passes through the points (0, –2) and (6, 1).<br><br> Find an equation of the line L.
lesya692 [45]

Answer:

Some Facts about lines (1) For non vertical line L, if L passes a point (x0,y0) with slope m, then an equation of line L is y − y0 = m(x − x0). (2) If a non vertical line L passes through distinct points (x1,y1) and x2(y2), then the slope of L is m = y2 − y1 x2 − x1 . x a + y b = 1.

Step-by-step explanation:

8 0
3 years ago
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The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10
Pepsi [2]
So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then 

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
y= 0.45



hope this helps :)





3 0
3 years ago
3. What is x?<br> E<br> 4x+ 5<br> H
frez [133]
What is the question
3 0
3 years ago
the bus to Leeds departs every 36 mins and the bus to Manchester leaves every 45 mins they leave the station at 10am one morning
Oliga [24]

Answer:

1 pm

Step-by-step explanation:

We have to find their LCM, or least common multiple

Multiples of 36: 36, 72, 108, 144, 180, 216, ......

Multiples of 45: 45, 90, 135, 180, ....

180 mins is their LCM.

180 mins = 3 hours

10am + 3hours = 1 pm

-Chetan K

6 0
2 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
2 years ago
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