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choli [55]
3 years ago
12

Y=-x^2-10x+24 What is the y value of the vertex?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0

Answer:

Step-by-step explanation:

1.) Get the equation in the form y = ax^2 + bx + c.

2.) Calculate -b / 2a. This is the x-coordinate of the vertex.

3.) To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

1.) y = -x^2 - 10x + 24

2.) -(-10) / 2(-1) = -5

3.) y = -(-5)^2 - 10(-5) + 24

    y = -25 + 50 + 24

    y = 49

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Hope this helps!
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<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
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=<span>e^2</span></span>
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