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3 years ago

Y=-x^2-10x+24 What is the y value of the vertex?

Mathematics

1 answer:

emmasim [6.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

1.) Get the equation in the form y = ax^2 + bx + c.

2.) Calculate -b / 2a. This is the x-coordinate of the vertex.

3.) To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

1.) y = -x^2 - 10x + 24

2.) -(-10) / 2(-1) = -5

3.) y = -(-5)^2 - 10(-5) + 24

y = -25 + 50 + 24

y = 49

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Determine the rate of change between the points (-1,-1) and (1,-1).

AVprozaik [17]

Answer:

$\displaystyle m = 0$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinate Planes

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Slope Formula: $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$

Step-by-step explanation:

*Note:

Rate of change is slope.

Step 1: Define

Identify.

Point (-1, -1)

Point (1, -1)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m.

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[Order of Operations] Simplify: $\displaystyle m = \frac{0}{2}$
Simplify: $\displaystyle m = 0$

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got it right :) hope this helped

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Write the slope intercept equation of the function f whose graph satisifies the given conditions. The graph of f passes through

MrMuchimi

Let's find slope first.

(1,-2)
(-8,6)

$\\ \sf\longmapsto m=\dfrac{6+2}{-8-1}$

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Slope intercept form

$\\ \sf\longmapsto y=mx+b$

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