Question

Can you solve for a,b and c 2a - 3b = -5 4a + 3b = 17 50 - 2a = 1

Answer 1

Answer:

$a = \frac{49}{2}$

$b = 18$

Step-by-step explanation:

Lets focus on the third equation to find a:

50 - 2a = 1

Add 2a to both sides of the equation:

50 - 2a + 2a = 1 + 2a

50 = 1 + 2a

Subtract 1 from both sides of the equation:

50 - 1 = 1 + 2a - 1

49 = 2a

Divide both sides by 2:

$\frac{2a}{2} = \frac{49}{2}$

$a = \frac{49}{2}$

Now substitute in the know a variable into the first equation:

$2a - 3b = -5$

$49 - 3b = -5$

Add 3b to both sides:

$49 - 3b + 3b = -5 + 3b\\49 = -5 + 3b$

Add 5 to both sides:

$49 + 5 = -5 + 3b + 5$

54 = 3b

Divide both sides by 3:

$\frac{53}{3} = \frac{3b}{3}$

$b = 18$

c cannot be solved as there is no c variable.

Hope this helps!