Question

Consider the line y=7x-3 fine the equation that pass through -5,6 of a perpendicular​

Answer 1

Answer:

$y=-\frac{1}{7}x+\frac{37}{7}$

Step-by-step explanation:

Your equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.  Your line has a slope of 7.  In order to find the line perpendicular to this line, we have to take the opposite reciprocal of the slope.  The perpendicular slope to m = 7 is m = -1/7.  Now we go through x = -5 and y = 6 to find the new equation.

6 = -1/7(-5) + b gives us

6 = 5/7 + b and

b = 37/7

Therefore, the equation of the line perpendicular to your original line is

$y = -\frac{1}{7}x + \frac{37}{7}$