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3 years ago

9

Consider the line y=7x-3 fine the equation that pass through -5,6 of a perpendicular

1 answer:

Pavel [41]3 years ago

5 0

Answer:

$y=-\frac{1}{7}x+\frac{37}{7}$

Step-by-step explanation:

Your equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. Your line has a slope of 7. In order to find the line perpendicular to this line, we have to take the opposite reciprocal of the slope. The perpendicular slope to m = 7 is m = -1/7. Now we go through x = -5 and y = 6 to find the new equation.

6 = -1/7(-5) + b gives us

6 = 5/7 + b and

b = 37/7

Therefore, the equation of the line perpendicular to your original line is

$y = -\frac{1}{7}x + \frac{37}{7}$

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3 years ago

What's the largest fraction in eaxh group? a. 5/6 and 29/36 b. 5/12 and 3/8 c.2/5 and 19/45 d.5/7, 13/14, and 19/21

Sever21 [200]

Answer:

a) $\frac{5}{6}$ is greatest fraction.

b) $\frac{5}{12}$ is greatest fraction.

c) $\frac{19}{45}$ is greatest fraction.

d) $\frac{13}{14}$ is greatest fraction.

Solution:

To compare two fraction we need to make denominator of both the fraction same.

a)Given fraction are $\frac{5}{6}$ and $\frac{29}{36}$

$\frac{5}{6}=\frac{5 \times 6}{6 \times 6}=\frac{30}{36}$

So $\frac{30}{36}$ is equivalent to $\frac{5}{6}$

So $\frac{30}{36}>\frac{5}{6}$

Hence $\frac{30}{36}$ that is $\frac{5}{6}$ is greater than $\frac{29}{36}$

b)Given fraction are $\frac{5}{12}$ and $\frac{3}{8}$

$\frac{5}{12}=\frac{5 \times 2}{12 \times 2}=\frac{10}{24}$

Similarly we get $\frac{3}{8}=\frac{3 \times 3}{8 \times 3}=\frac{9}{24}$

So $\frac{10}{24}>\frac{9}{24}$

$\frac{10}{24}>\frac{9}{24}$

That is $\frac{5}{12}>\frac{3}{8}$

Hence $\frac{5}{12}$ is greater than $\frac{3}{8}$

c) Given fraction are $\frac{2}{5}$ and $\frac{19}{45}$

$\frac{2}{5}=\frac{2 \times 9}{5 \times 9}=\frac{18}{45}$

So $\frac{19}{45}>\frac{18}{45}$

That is $\frac{19}{45}>\frac{2}{5}$

Hence $\frac{19}{45}$ is greater than $\frac{2}{5}$

d)Given fraction are $\frac{5}{7}$ , $\frac{13}{14}$ and $\frac{19}{21}$

$\frac{5}{7}=\frac{5 \times 6}{7 \times 6}=\frac{30}{42}$

$\frac{13}{14}=\frac{13 \times 3}{14 \times 3}=\frac{39}{42}$

Similarly we get

$\frac{19}{21}=\frac{19 \times 2}{21 \times 2}=\frac{38}{42}$

So $\frac{39}{42}>\frac{38}{42}>\frac{30}{42}$

That is $\frac{13}{14}>\frac{19}{21}>\frac{5}{7}$

Hence $\frac{13}{14}$ is greatest fraction.

4 0

3 years ago

katrin2010 [14]

Answer:

Answer to part a. is 169/16. Answer to part b. is 84.5.

Step-by-step explanation:

5 0

4 years ago