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3 years ago

Consider the line y=7x-3 fine the equation that pass through -5,6 of a perpendicular

Mathematics

1 answer:

Pavel [41]3 years ago

5 0

Answer:

$y=-\frac{1}{7}x+\frac{37}{7}$

Step-by-step explanation:

Your equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. Your line has a slope of 7. In order to find the line perpendicular to this line, we have to take the opposite reciprocal of the slope. The perpendicular slope to m = 7 is m = -1/7. Now we go through x = -5 and y = 6 to find the new equation.

6 = -1/7(-5) + b gives us

6 = 5/7 + b and

b = 37/7

Therefore, the equation of the line perpendicular to your original line is

$y = -\frac{1}{7}x + \frac{37}{7}$

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Consider the line y=7x-3 fine the equation that pass through -5,6 of a perpendicular​

Consider the line y=7x-3 fine the equation that pass through -5,6 of a perpendicular