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stiv31 [10]
2 years ago
13

A. Only sequence A B. Only sequence B C. Both D. Neither 30 POINTS OMG

Mathematics
2 answers:
e-lub [12.9K]2 years ago
8 0
B. Only sequinse B as fydydugiryryglgirur
Phoenix [80]2 years ago
7 0
B. Only Sequence B

The one with the reflection over the line HI and then the 6 unit translation to the right
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Which expression is equivalent to 24x+18y
scZoUnD [109]

Answer:

A- 6 (4x) + 3 (6y)

Step-by-step explanation:

6 (4x) + 3 (6y) equals 24x+18y

3 0
2 years ago
Which of the following inequalities is correct?
almond37 [142]

Answer:

A

Step-by-step explanation:

because there variables represent 1 so 1 cant be bigger than one and the other two have real equations

6 0
2 years ago
What is equivalent to 5 squared times 9 squared
Pepsi [2]

Answer:

2,025

Step-by-step explanation:

5 squared is 5x5 = 25

9 squared is 9x9 = 81

25x81 = 2,025

4 0
3 years ago
I could use some help
dalvyx [7]
Option A, it’s the base times the height
4 0
2 years ago
Read 2 more answers
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi
yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let p_1 = <u><em>percentage of employed workers who have registered to vote.</em></u>

p_2 = <u><em>percentage of unemployed workers who have registered to vote.</em></u>

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, H_A : p_1>p_2     {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here <u>Two-sample z test for proportions;</u>

                          T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of employed workers who have registered to vote = \frac{287}{513} = 0.56

\hat p_2 = sample proportion of unemployed workers who have registered to vote = \frac{280}{604} = 0.46

n_1 = sample of employed persons = 513

n_2 = sample of unemployed persons = 604

So, <u><em>the test statistics</em></u>  =  \frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }

                                       =  3.349

The value of z test statistics is 3.349.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0
2 years ago
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