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3 years ago

5. During a Cougars' basketball game, the ratio of baskets

1 answer:

8 0

You see the ratio is 2/5 and x is supposed to represent the total attempted baskets. The ratio is 2/5 and x is the total attempted baskets

Mark brainliest please

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Un escalador sube 225m de altura. El asenso lo hizo en 3 etapas. En la primera subio un quinto en la, en la tercera un cuarto. ¿

kiruha [24]

Answer:

Segunda etapa= 123.75 metros

Step-by-step explanation:

Altura total= 225 metros

En la primera estapa subió el 20% (un quinto):

Primera etapa= 225*0.2= 45 metros

En la tercera etapa subió 25% (un cuarto):

Tercera etapa= 225*0.250 56.25 metros

Ahora debemos determinar cuánto subió en la segunda etapa:

Segunda etapa= altura total - total subido

Segunda etapa= 225 - (45 + 56.25)

Segunda etapa= 123.75 metros

6 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

4 years ago

I need help with this can someone please help me I'm bad at fractions.

Artemon [7]

The answer is 29, I just didn’t on my head right now.

5 0

3 years ago

How much more interest will Maria receive if she invests $1,000 for one year at x percent annual interest, compounded semiannual

notka56 [123]

Answer:

$0.025x² . . . where x is a number of percentage points

Step-by-step explanation:

The multiplier for semi-annual compounding will be ...

(1 + x/2)² = 1 + x + x²/4

The multiplier for annual compounding will be ...

1 + x

The multiplier for semiannual compounding is greater by ...

(1 + x + x²/4) - (1 + x) = x²/4

Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.

If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...

$250·(x/100)² = $0.025x² . . . where x is a number of percentage points

_____

Example:

For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.

3 0

3 years ago

Leeza is making labels in the shape of parallelograms Each label has an area of 18 square centimeters and a base of 6 centimeter

stich3 [128]

I think it's 3

It should be 3 because if you have a base of 6 then your height must be 3 to get 18.

5 0

4 years ago

Read 2 more answers