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Reika [66]
4 years ago
10

In a random sample of egg cartons, a supermarket finds that 3 cartons in every 50 cartons contain cracked eggs. If the supermark

et receives a shipment of 400 cartons, how many cartons can they expect will contain cracked eggs? A. 24 cartons B. 30 cartons C. 14 cartons
Mathematics
1 answer:
denis-greek [22]4 years ago
8 0

\frac{3}{50} =\frac{x}{400}. Cross multiply: 1200=50x. Divide both sides by 50; therefore, x=24/A.

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An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 3ft long with a diameter of 2.2 ft . S
Contact [7]

4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5 ft^{3} per minute.

Step-by-step explanation:

              The given is,

                         Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.

                          Oil drained at a rate of 2.5 ft^{3} per minute.

Step:1

       Time taken to dry the oil tank is,

                           T   = \frac{Volume of oil}{Oil drain rate}  ....................................(1)

Step:2

      Volume of the oil is,

                           V = \pi  r^{2} h.................................................(2)

      Where, r - Radius of Cylinder

                             r = \frac{d}{2}

                             r = \frac{2.2}{2}

                             r = 1.1 ft

      From eqn (1),

                        V =  \pi × 1.1^{2} × 3

                           = 11.40398 ft^{3}

Step:3

     From equation (1)

                           = \frac{11.40398}{2.5}

                           = 4.56

                           = 4.56 minutes

                      T  = 4 minutes 34 seconds

Result:

      Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.

4 0
3 years ago
Choose one of the factors of 1331x3 − 8y3.
daser333 [38]
B is the answer hope this helps :)
7 0
3 years ago
Read 2 more answers
An investment strategy has an expected return of 15 percent and a standard deviation of 9 percent. Assume investment returns are
IgorLugansk [536]

Answer:

68% of an investment earning a return between 6 percent and 24 percent.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 15

Standard deviation = 9

How likely is it to earn a return between 6 percent and 24 percent?

6 = 15 - 1*9

6 is one standard deviation below the mean

24 = 15 + 1*9

24 is one standard deviation above the mean

By the empirical rule, there is a 68% of an investment earning a return between 6 percent and 24 percent.

6 0
3 years ago
How would you describe the relationship between the real zeros and x-intercepts of the function y = log (x-2)?
lakkis [162]

Answer:

When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.

Step-by-step explanation:

The given function is y=\log (x - 2).

So, for real zeros and x-intercept, the y-coordinate must be equal to zero.

Then it becomes 0 = \log (x-2)

⇒ x - 2 = 1 {Since log 1 = 0}

⇒ x = 3

Therefore, when you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3. (Answer)

3 0
3 years ago
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jeyben [28]
It’s the mean!
good luck!!
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3 years ago
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