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Elan Coil [88]
3 years ago
12

Mathematician involved in the development of percentage​

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

Answer:

No one person invented percentages. The concept developed throughout history. In Ancient Rome mathematical computation were expressed in fractions of 100.

Step-by-step explanation:

The term has been attributed to Latin per centum. The concept of considering values as parts of a hundred is originally Greek. The symbol for percent (%) evolved from a symbol abbreviating the Italian per cento. In some other languages, the form procent or prosent is used instead.

Hope this helps

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9x+5y=8<br> 3x–y=4<br> what is the y-value of the solution to the system?
CaHeK987 [17]

Answer:

y=7.51

Step-by-step explanation:

First, you have to simplify one of the equations down

3x-y=4

y=-4+3x

Second, you insert the value of y into the other equation and then solve for x

9x+5(-4+3x)=8

9x-20+15x=8

24x=28

x=1.17

Last, insert the value of x into the original equation and then solve for y

y=4+3(1.17)

y=7.51

3 0
3 years ago
Geometry please help!
o-na [289]

Answer:

x = 3

Step-by-step explanation:

Angle S and Angle T are consecutive interior angles. Therefore, we know that T + S = 180°.

First, we need to solve for T, and since angles S and T are consecutive interior angles, we know that T + S = 180°. If we reorganize the equation to include the things we know (S = 105°), then we get 180° - 105° = 75°. So T is 75°.

Now, we use T = 75° and the information given to us in the picture to set up an equation. 75 = 24x + 3. Now, we can find x by isolating it. Do this by:

1) Subtracting 3 from both sides to give you 72 = 24x. We do this to get rid of the 3 from the "x side", but we must also do it to the other to keep the equation true. This moves the 3 from the "x side" to the other since we're trying to isolate x.

2) Divide 24 by both sides to get 3 = x. We use the same logic as we did for 3, except this time we divide since that's the opposite of multiplying.

In conclusion, x = 3.

6 0
2 years ago
The area of a trapezoid is found using the formula A=1/2h(b^1+b^2), where b^1 and b^2 are the parallel sides of the trapezoid an
OverLord2011 [107]

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{1}{2}h(b_1+b_2)~~ \begin{cases} A=18\\ b_1=5\\ b_2=7 \end{cases}\implies 18=\cfrac{1}{2}h(5+7) \\\\\\ 18=\cfrac{h(12)}{2}\implies 18=6h\implies \cfrac{18}{6}=h\implies 3=h

3 0
3 years ago
Which of the following statements are true?
Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is false.

B.  The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is true.

C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

D. The function f(x)=\dfrac{1}{2}\sqrt{x} has the domain and the range all non-negative real values. The function  f(x)=\sqrt[3]{x} has the domain and the range all real values. So this option is false.

3 0
3 years ago
Need help with son's homework I will give 30 points!!! Please show work
Elis [28]

Answer:

A. ⇒ The expression is b + 3

B. ⇒ The expression is 2b - 4

C. ⇒ The Dr's office is closer by 4 miles

Step-by-step explanation:

A.

∵ The distance between Daniel's house and his school is b miles

∵ The swimming pool is 3 miles farther from his school

∴ The distance between Daniel's house and the swimming pool is b + 3

B.

∵ The distance from Daniel's house to his Dr's office is 4 less than twice the distance from home to Daniel's school

∵ The distance between Daniel's house and his school is b

∴ The expression of distance from Daniel's house to his Dr's office is

   2b - 4

C.

∵ b = 3

∴ The distance between his house and swimming pool is:

   3 + 3 = 6 miles

∴ The distance between his house and Dr's office is:

   2(3) - 4 = 2 miles

∴ The Dr's office is closer to Daniel's house than the swimming pool by:

   6 - 2 = 4 miles

6 0
3 years ago
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