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makvit [3.9K]
3 years ago
7

The ratio of the number of cups of yellow paint to the number of cups of blue paint that Greg mixed to make a shade of green pai

nt is 2:1.
Part A: Write a sentence to describe the number of cups of yellow paint that Greg mixed with each cup of blue paint. (4 points)

Part B: How many cups of blue paint should Greg add to each cup of yellow paint to make the shade of green? Explain your reasoning. (4 points)

Part C: If Greg purchased 6 cups of yellow paint for $54, what is the unit price per cup of yellow paint? (2 points)
Mathematics
2 answers:
Blababa [14]3 years ago
6 0

Answer:

I swear I don't know if I knew I would tell you but I don't

Step-by-step explanation:

artcher [175]3 years ago
4 0

Answer:

kanna Sprite kudi answere yosi

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Help pls I have no clue how
Goryan [66]

Answer:

Step-by-step explanation:

By using regression line calculator,

Equation of the regression line from the data given,

y = -0.38993x + 26.95184

Here, y = weekly hours of sport

x = Time to run

For x = 50 minutes,

y = -0.38993(50) + 26.95184

  = 7.45534

  ≈ 8

Since, slope of the given regression line is negative, correlation will be negative (n).

3 0
3 years ago
Jay King, owner of a local Bed and Bath Store knows that his customers will only pay at most, $299 for a blow up bed. Assuming J
N76 [4]
The answer would be 747.50! Because if you were wanting to decrease the price then you would multiply $299 by 40% So since you are wanting to add to the price then you would divide...Hope that makes since :)
8 0
4 years ago
Read 2 more answers
Two independent samples of sizes 20 and 30 are randomly selected from two normally distributed populations. Assume that the popu
aleksley [76]

Answer:

b. Student-t with 48 degrees of freedom

Step-by-step explanation:

For this case we need to use a Two Sample t Test: equal variances.

Assumptions

When running a two-sample equal-variance t-test, the basic assumptions are "that the distributions of the two  populations are normal, and that the variances of the two distributions are the same".

Let \bar x and \bar y be the sample means of two sets of data of size n_x and n_y respectively. We assume that the distribution's of x and y are:

x \sim N(\mu_x ,\sigma_x =\sigma)

y \sim N(\mu_y ,\sigma_y=\sigma)

Both are normally distributed but without the variance equal for both populations.

The system of hypothesis can be:

Null hypothesis: \mu_x =\mu_y

Alternative hypothesis: \mu_x \neq \mu_y

We can define the following random variable:

t=\frac{(\bar x -\bar y)-(\mu_x -\mu_y)}{s\sqrt{\frac{1}{n_x}+\frac{1}{n_y}}}

The random variable t is distributed t \sim t_{n_x +n_y -2}, with the degrees of freedom df=n_x +n_y -2= 20+30-2=48

And the pooled variance can be founded with the following formula:

s^2=\frac{(n_x -1)s_x^2 +(n_y-1)s_y^2}{n_x +n_y -2}

So on this case the best answer would be :

b. Student-t with 48 degrees of freedom

5 0
3 years ago
What is 140.23 < 140.203 is the answer true or false?
Nitella [24]

Answer:

False

Step-by-step explanation:

140.23 bigger (>) than 140.203

8 0
3 years ago
Read 2 more answers
How do you find 3x + 5
tiny-mole [99]
It must be an equation in order to be solved  for example, 3x+5=11  then x would be 2
3 0
3 years ago
Read 2 more answers
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