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Kay [80]
3 years ago
13

Someoen pelaseee help

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

A: -x-3≤-8

Step-by-step explanation:

-11-3≤-8

-14≤-8

-14 is less than or equal to -8.

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If y varies directly and y is 12 when x is 1.2 what is the constant of variation for this relation
sergij07 [2.7K]

Answer:

10

Step-by-step explanation:

The constant of variation would be 12 / 1.2 = 10.

7 0
3 years ago
Read 2 more answers
which second-degree polynomial function has a leading coefficient of -1 and root 4 with multiplicity 2
olchik [2.2K]

Answer:

  f(x) = -x^2 +8x -16

Step-by-step explanation:

With the given data, we can write the factored function as ...

  f(x) = -1(x -4)^2 . . . . . -1 is the leading coefficient; exponent of 2 gives root multiplicity

  f(x) = -x^2 +8x -16

5 0
4 years ago
Simplify the expression below. (10x+1)3x+5(5x)
Katen [24]

Answer:

38x

Step-by-step explanation:

{(10x+1)3x}+5(5x)

10x+3x+25x=38x

5 0
3 years ago
Read 2 more answers
Help please this is due in 10 minutes.<br> Help!
garri49 [273]

Those are supplementary,

(x+8) + (3x+2) = 180

4x + 10 = 180

4x = 170

x = 170/4 = 85/2 = 42.5 degrees

x+8 = 50.5 degrees

3x+2 = 129.5 degrees

I think I just answered this question yesterday


7 0
3 years ago
Darin bought a new pair of soccer cleats for $59.99. The sales tax is 6.5%. What is the total cost in dollars that Darin will pa
DaniilM [7]
Hello there! So, we find the total cost in dollars by multiplying the price of the cleats by the percent of tax. However, we first need to add 1 to the tax rate in decimal form. 6.5% is 0.065 in decimal form. Now add 1 to that number to get 1.065. Let's multiply. 59.99 * 1.065 is 63.88935 or 63.89 when rounded to the nearest hundredth. There. Darin will pay a total of $63.89.

Note: When it comes to finding the total price of something with tax, add 1 to the percentage rate in decimal form, and then multiply that number by the price to get the total amount. This will help you out, make things easier, and save time.
5 0
4 years ago
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