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zlopas [31]
3 years ago
13

3t+19=6 what is t equal?

Mathematics
2 answers:
skad [1K]3 years ago
8 0
The answer is
3t=-13
t=-13/3
Licemer1 [7]3 years ago
6 0
Well I don't know.
Let's you and me get together and figure it out.

You said that . . . . . . . . . . . . . . 3t + 19 = 6

Subtract 19 from each side . . . 3t = -13

Divide each side by 3 . . . . . . . t = -13/3

Did I go too fast for you ?
You might be interested in
We bought 3 pairs of socks and 2 handkerchiefs for $ 1.45 and, yesterday, 2 pairs of stocking and 5 handkerchiefs for $ 1.75. De
alexgriva [62]
Equations for the numbers of pairs of socks (s) and handkerchiefs (h) can be written as
  3s +2h = 1.45
  2s +5h = 1.75

These can be solved by any of your favorite means to find
  s = 3.75/11 ≈ 0.341
  h = 2.35/11 ≈ .214

The price of a pair of socks and a handerchief is $0.34 +0.21 = $0.55.
6 0
3 years ago
Piravena must make a trip from A to B then from B to C, then from C to A. Each of these three parts of the trip is made entirely
anyanavicka [17]

Answer:

a) Cost of flying from A to B = $425

b) Total distance travelled by Piravena during the complete trip = 7,500 km

c) To minimize cost and arrive at the final cost given, she must have travelled by bus from B to C and then travelled by taking an airplane from C to A.

Step-by-step explanation:

The complete question is presented in the attached image to this question.

Full Question

a) To begin her trip she flew from A to B. Determine the cost of flying from A to B.

b) Determine the distance she travels for her complete trip.

c) Piravena chose the least expensive way to travel between cities and her total cost was $1012.50. Given that she flew from A to B, determine her method of transportation from B to C and her method of transportation from C to A.

Solution

a) The distance from A to B is given as 3250 km.

To take an airplane, it costs her a $100 booking fee, plus $0.10 per kilometer.

So, to fly 3250 km, she will pay

100 + (0.10×3250) = $425

b) For her complete journey, she is to make a trip from A to B then from B to C, then from C to A.

Her complete distance travelled = AB + BC + CA

But it is given that the three cities form a right angled triangle as given in the question with AB serving as the hypotenuse side.

Pythagoras theorem gives that the square of the hypotenuse side is equal to the sum of the respective squares of the other two sides

AB² = BC² + CA²

3250² = BC² + 3000²

BC² = 3250² - 3000² = 1,562,500

BC = √1,562,500 = 1,250 km

Total distance covered by Piravena during the entire trip = AB + BC + CA = 3250 + 1250 + 3000 = 7,500 km

c) Her total cost of travel = $1012.50

But she definitely flew from A to B at a cost of $425

This means she spent (1012.50 - 425) on the rest of the journey, that is, $587.5

Note that to travel by bus, it is $0.15 per kilometre and to travel by airplane is $100 + $0.10 per kilometre. Indicating that the airplane saves cost on long distance travels while the bus saves cost on short distance travels.

To confirm this, we calculate the two options (bus or airplane) for each route.

If she travels B to C by bus, cost = 0.15 × 1250 = $187.5

If she travels B to C by airplane, cost = 100 + (0.10×1250) = $225

Hence, the bus obviously minimizes cost here.

If she travels from C to A by bus, cost = 0.15 × 3000 = $450

If she travels from C to A by airplane, cost = 100 + (0.10×3000) = $400

Here, travelling by airplane minimizes the cost.

So, if we confirm now that she travelled from B to C by bus and then from C to A by airplane, total cost = 187.5 + 400 = $587.5

which is the remaining part of her total cost is she minimized expenses!

Hope this Helps!!!

7 0
3 years ago
Thanks to all my new followers ​
solniwko [45]

Answer:

np

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Can someone help me out rq pls? Much would be appreciated.
stich3 [128]
I think your answer is B. -1/2

Explanation: the rise is -4 and the run is 8. If u divide those by 2, you get -2 and 4. You divide that by half and get -1/2??
8 0
2 years ago
P (6,6) y=2/3x
matrenka [14]

Answer:

y = -\frac{3}{2}x+15

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

y-intercept c=0

We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

So, the slope of the perpendicular line m_{2}=-\frac{3}{2}

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

c=6+9

c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

8 0
3 years ago
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