3 years ago

2. How long does this lease last?

Mathematics

1 answer:

Tatiana [17]3 years ago

7 0

Answer:

akeijd

Step-by-step explanation:

kahshsarihaieie

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The relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is $\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Given the following parameters:

Adjacent side = x

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$\frac{d \theta}{dx} = \frac{h}{x\sqrt{x^2+y^2} }$

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$\frac{d\theta}{dt} =\frac{d\theta}{dx} \times \frac{dx}{dt}\\\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Hence the relationship between dθ/dt, the rate of change of θ with respect to time, and dx/dt, the rate of change of x with respect to time is $\frac{d\theta}{dt} = \frac{h}{x\sqrt{x^2+y^2} }\frac{dx}{dt}$

Learn more on the rate of change here: brainly.com/question/11883878

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