All categories

3 years ago

This is a 30-60-90 triangle. What is the measure of x? 18 X X x = 9V [?]

Mathematics

1 answer:

sammy [17]3 years ago

5 0

Answer:

$\huge\: x =9 \sqrt{ \boxed{3}}$

Step-by-step explanation:

Given is a 30°-60°-90° triangle and x is the length of side opposite to 60° angle.

$\therefore \: x = \frac{ \sqrt{3} }{2} \times 18 \\ \\ \therefore \: x = \sqrt{3} \times 9 \\ \\ \huge\therefore \: x =9 \sqrt{ \boxed{3}}$

You might be interested in

4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the

s2008m [1.1K]

Answer:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = $2a$

where $a$ is called the semi-major axis.

In this case since the major axis is equal to 10 units:

$10=2a$

solving for the semi-major axis $a$ :

$a=10/2\\a=5$

and also the minor axis of an ellipse is represented as:

Minor axis = $2b$

where $b$ is called the semi-minor axis.

Since the minor axis has a length of 8 units:

$8=2b$

solving for b:

$b=8/2\\b=4$

Now we can use the equation for an ellipse centered at the origin (0,0):

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

and substituting the values for $a$ and $b$ :

$\frac{x^2}{5^2} +\frac{y^2}{4^2} =1$

and finall we simplify the expression to get the equation of the ellipse:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

5 0

3 years ago

A rock dropped on the moon will increase its speed from 0 m/s (its starting

belka [17]

<h2>Hello!</h2>

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!

7 0

3 years ago

Please assist me in my time of need.

vaieri [72.5K]

Answer:

I shall assist thee.

Step-by-step explanation:

Being me, I would say the answer is A. or B. But i'd prolly go with A tbh.

And oofers on me if this ain't what you need.

4 0

3 years ago

Simplify:<br> (4p3 + 6p2 – 7) – (8p? – 7 – 3p)

Kipish [7]

Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2" was replaced by "p^2". 1 more similar replacement(s).

STEP

Equation at the end of step 1

(((4 • (p3)) + (2•3p2)) - 7) - 8p

STEP

Equation at the end of step

((22p3 + (2•3p2)) - 7) - 8p

STEP

Checking for a perfect cube

3.1 4p3+6p2-8p-7 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -8p-7

Group 2: 4p3+6p2

Pull out from each group separately :

Group 1: (8p+7) • (-1)

Group 2: (2p+3) • (2p2)

3.3 Find roots (zeroes) of : F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of p for which F(p)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers p which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 4 and the Trailing Constant is -7.

The factor(s) are:

of the Leading Coefficient : 1,2 ,4

of the Trailing Constant : 1 ,7

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 3.00

-1 2 -0.50 -2.00

-1 4 -0.25 -4.69

-7 1 -7.00 -1029.00

-7 2 -3.50 -77.00

-7 4 -1.75 3.94

1 1 1.00 -5.00

1 2 0.50 -9.00

1 4 0.25 -8.56

7 1 7.00 1603.00

7 2 3.50 210.00

7 4 1.75 18.81

Final result :

4p3 + 6p2 - 8p - 7

5 0

3 years ago

Can somebody match these for me .

Harlamova29_29 [7]

From left to right - (-2,6) (4,1) (-2,5) top (1,-3) bottom (-4,-1) (2,-5)

8 0

3 years ago