Answer:
A = 82.53 in²
Step-by-step explanation:
We use the circumference equation C = 2πr and the area equation A = πr².
Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.
C 32 in
C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in
2π 6.28
Then the area of the circle is A = πr², which here is A = 3.14(5.10 in)², which, when rounded off to two decimal places, is A = 82.53 in²
Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
2x+y=3
- x+y=5
---------------
x=-2
2(-2)+y=3
y=7
-2+y=5
y=7
(-2,7)
(180-30)/2 would be the equation and the answer is 150/2
