Answer:
a marketable service
Explanation:
that should be the answer
There are different kinds of theory. The chemical equation that does not correspond to a standard molar enthalpy of formation is c. N₂(g) + O₂(g) ⇒ 2 NO(g).
<h3>What is standard enthalpy of formation ?</h3>
The standard enthalpy of formation of any element is known to often occur in the standard state that is zero of that element.
For example, even though oxygen can be found as ozone (O3), O2 is the known to be the most stable form.
Learn more about standard enthalpy of formation from
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The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.
<h3>How to determine the mole of NaHCO₃</h3>
- Molarity of NaHCO₃ = 2 M
- Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
- Mole of NaHCO₃ =?
Mole = Molarity x Volume
Mole of NaHCO₃ = 2 × 0.0316
Mole of NaHCO₃ = 0.0632 mole
<h3>How to determine the mole of CO₂</h3>
NaHCO₃ + HCl —> CO₂ + H₂O + NaCl
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.
Thus, 0.0632 mole of CO₂ was obtained from the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
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