2 years ago

Please someone help me i need this done asap!

Mathematics

2 answers:

Sedbober [7]2 years ago

5 0

Answer:

4.41 x 10^3 hope this helps

12345 [234]2 years ago

4 0

Answer:

32000 is your answer its not to hard all you got to do is type it into the calculator and press enter

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2r+c+0.5d+8 how many terms does the expression have

Lemur [1.5K]

A term in a math expression is single number or variable and are separated by a + or - or × or ÷

This expression has 4 terms

.5d

and 8

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3 years ago

Multiply both sides of the equation by 6. {(4a + 1) = 2a ? (4a + 1) = ? a

solniwko [45]

Answer:

24a+6=12a

Step-by-step explanation:

6(4a+1)

24a+6

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3 years ago

On line A, each time x increases by 1 y increases by

kompoz [17]

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y increases by 2

Step-by-step explanation:

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3 years ago

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Cuántas diagonales tendría una figura de 8 lados?

Oduvanchick [21]

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Step-by-step explanation:

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2 years ago

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Find the values of k so that each remainder is three. 10. (x^2+ 5x + 7) = (x + k)

Goryan [66]

Answer:

$k=1\text{ or } k=4$

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a binomial in the form (x - a), then our remainder will be P(a).

We are dividing:

$(x^2+5x+7)\div(x+k)$

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

$(-k)^2+5(-k)+7=3$

Simplify:

$k^2-5k+7=3$

Solve for k. Subtract 3 from both sides:

$k^2-5k+4=0$

Factor:

$(k-1)(k-4)=0$

Zero Product Property:

$k-1=0\text{ or } k-4=0$

Solve:

$k=1\text{ or } k=4$

So, either of the two expressions:

$(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)$

Will yield 3 as the remainder.

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3 years ago