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elena-14-01-66 [18.8K]
2 years ago
11

"8% of a number is 20."

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
5 0

Answer: 250

Step-by-step explanation:

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14×12 distributive property​
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5 0
3 years ago
Please hurry I will mark you brainliest.
ivann1987 [24]

Answer:

12862.83cm³

Step-by-step explanation:

Volume of the Box: [L×W×H] or [30x30x30] or [27000cm³]

Volume of the Sphere: [\frac{4}{3}\pi r^{3}] (\pi=pi=3.14) (r=radius=15) or [\frac{4}{3}×3.14×3375] or [14137.17cm³]

Volume of the empty space: 27000cm³-14137.17cm³=12862.83cm³

Btw there are online tools to help you find the volume of a sphere (just use it after you understand the equation)

Hope I helped!

4 0
2 years ago
Help me find the scale factor please!!
Oliga [24]

Answer:1.5 i think

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0
3 years ago
Read 2 more answers
02.05) simplify i22. (1 point) 1 −1 −i i
olga2289 [7]
I^22 = i^(20 + 2) = i^20 x i^2 = (i^4)^(5) x (i)^2 = 1 x -1 = -1
7 0
3 years ago
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