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Talja [164]
3 years ago
13

If it took 10 hours to mow 8 lawns, then at that rate, how many lawns could be mowed in 30 hours?

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

24 Lawns

Step-by-step explanation: If it took 10 hours to mow 8 lawns, then add 8 to its self 3 times and you get 24.

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What is 0.75% of 387
luda_lava [24]

Answer: 2.9025


Step-by-step explanation:

0.75 x 387/100  

= 2.9025

3 0
4 years ago
Read 2 more answers
Please help with number 4,5,6,7,8 it will mean a lot
Xelga [282]
5) The slope is: 6

6) Answer: y=-1/2x+3

7) Answer: The slope is: -8, the y intercept is: 6

8) Answer: y=8x+30

Have a good day and a hug :D づ◡﹏◡)づ
6 0
3 years ago
In order to test for the significance of a regression model involving 3 independent variables and 47 observations, the numerator
matrenka [14]

Answer:

The correct option is  C

Step-by-step explanation:

From the question we are told that

     The number of independent variables is  n =  3

     The number of observation is  z =  47

     

Since n is are independent variables then their degree of freedom is  3

   The  denominator(i.e z) degrees of freedom is evaluated as

            Df(z) =  z - (n +1)

          Df(z) =  47 - (3 +1)

          Df(z) =  43

So for the numerator (n) the degree of freedom is  Df(n) = 3

So for the denominator(i.e z) the degree of freedom is  Df(z) = 43

4 0
4 years ago
6. The population of a town is 680 000 correct to the nearest 10 000. Write down
serg [7]

Answer:

a) 675 000

b) 685 000

Step-by-step explanation:

The population of a town is 680 000 correct to the nearest 10 000.

a) To find it lower bound, we level of accuracy by 2 and then subtract from 680 000

The lower bound is:

680 000-5000=675,000

Therefore the least possible population of the town is 675 000

b) We repeat the same process to find the upper bound

680 000+5000=685,000

6 0
3 years ago
Line AB is tangent to circle O at A. The diagram is not drawn to scale.
Arlecino [84]
AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
<span>Line AB is tangent to circle O at A</span>
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴  OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28
<span />
8 0
4 years ago
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