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BaLLatris [955]
3 years ago
15

The phone company A Fee and Fee has a monthly cellular plan where a customer pays a flat

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

<u>The equation is:</u>

  • y = mx + b

<u>We have two points:</u>

  • (310, 68) and (620, 99)

A)

<u>Find the slope using these two points:</u>

  • m = (99 - 68)/(620 - 310) = 31/310 = 0.1

<u>Use one of the points to find the y-intercept b:</u>

  • 68 = 0.1*310 + b
  • 68 = 31 + b
  • b = 68 - 31
  • b = 37

<u>The equation is:</u>

  • y = 0.1x + 37

B)

<u>Find the value of y when x = 980:</u>

  • y = 0.1*980 + 37
  • y = 98 + 37
  • y = 135

The total cost is $135

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stira [4]

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3 years ago
Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

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3 years ago
(x+3)^2 and x^2+9 is equivalent?
chubhunter [2.5K]
They are not equivalent, try adding in numerical values for x, both do not come out the same.
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3 years ago
In which quadrant is (-1/2, -1.8)?
andrey2020 [161]
X = -1/2 (negative)
y = - 1.8 (negative)

so It's in Quadrant 3
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3 years ago
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