It is £15 for the words, but I don’t understand the second part
If you would like to know the Tom's pay for the week, you can calculate this using the following steps:
P = B * h
P ... the pay
B ... the base pay
h ... the number of hours worked
B = $6.35
h = 28 hours
P = B * h = $6.35 * 28 hours = $177.8
<span>Tom's pay for the week would be $177.8.</span>
Question options:
A. He should report them directly on form 1040
B. He should report them on form 8949 and then on schedule D
C. He should report them on schedule D
D. He is not required to report them until he sells the underlying securities
Answer:
B. He should report them on form 8949 and then on schedule D
Explanation:
John has shares which have capital gains from a mutual fund and a brokerage account. In order to report his taxes, he would need to use the Schedule D(form 1040) for his mutual fund capital gains and the form 8949 for his brokerage capital gains. The brokerage capital gains is then transferred to schedule D.
You're trying to find constants

such that

. Equivalently, you're looking for the least-square solution to the following matrix equation.

To solve

, multiply both sides by the transpose of

, which introduces an invertible square matrix on the LHS.

Computing this, you'd find that

which means the first choice is correct.
Answer:
0.51 liters in the glass
Step-by-step explanation:
Given


Required
Determine how many liters in the glass
To do this, we simply multiply the fraction poured by the total.
So, we have:




<em>There will be 0.51 liters in the glass</em>